3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.
Explanation:
data given:
H30+= 1.40 X 10^-4 M\
Henderson Hasslebalch equation to calculate pH=
pH = -log10(H30+)
putting the values in the equation:
pH = -log 10(1.40 X 10^-4 M)
pH = 3.85
pH + pOH =14
pOH = 14 - 3.85
pOH = 10.15
The OH- concentration from the pOH by the equation:
pOH = -log10[OH-]
10.5= -log10[OH-]
[OH-] = 10^-10.5
[OH-] = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.
Answer:
The pH is 4.76 (option C)
Explanation:
pH of a solution = TO BE DETERMNED
[sodium acetate] = 1M ; [acetic acid] = 1M
K = [H+] [A-] / [HA]
K = [H+] [1] / [1]
K = H
pH = pK
⇒ now pH is equal to pK
⇒ The value of pK is given which is 4.76
⇒ This means the value of the pH is also 4.76
Answer:
The water will eventually become the same temature (A)
Answer:
0.234 moles
Explanation:
moles of Al2O3 = mass / molar mass
moles of Al2O3 = 23.87g / 102.0g/mol
moles of Al2O3 = 0.234 moles (to three significant figures)
75 x 3 = ______
Well if you take 75 plus 75 you get 150 Fish ,Then you add 75 more so 150 plus 75 equals 225 So there are 225 fish in display at the entrance.
hope this helps please mark brainliest !!!!!!!!!!!!
