A. If motion starts and stops at the same location, then the displacment is zero.
D. Distance is always greater than or equal to the magnitutde of the displacement.
Answer:
We can't see the options so we don't know what we can put
Explanation:
Answer:
C. The balloon with CH4 has the same moles of gas molecules as the balloon with H2
Explanation:
Based on combined gas law, gases under the same pressure, temperature and volume have the same number of moles. With this information we can say the rigth statement is:
<h3>C. The balloon with CH4 has the same moles of gas molecules as the balloon with H2</h3>
So to balance an equation, you need to get the same amount of each type of element on either side of the --> . So you pretty much are given the subscripts in the equations and you need to add coefficients (just normal numbers) in front of any formula that needs it, keeping anything balance.

turns into

These coefficient numbers are the molar ratios, so 2 moles of KCl3 for every 3 moles of O2 so 1. 3:2
Then you can use these ratios of find out how many moles of one thing are needed if you are given the amount of another.

and use cross multiplication to solve for whatever you don't know
<span />
1 is true,
<span>2 is definitely false </span>
<span>3 is also completely false because </span>
<span>4 is true. </span>
<span>So 1&4 </span>