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Anna11 [10]
3 years ago
13

Two large books are stacked on top of each other on a table . The mass of each book is 6.5Kg Given that the coefficient of stati

c friction between bottom book and table is 0.15, what is the lowest the coefficient of static friction between the books can be in order to apply force and move both books?
Physics
1 answer:
Setler [38]3 years ago
3 0
<span>If you apply force (push) both books with the same energy at the same constant rate then the friction between them doesn't matter as both will move. If you push on the bottom book only, the friction between the books needs to be sufficient that the top book is carried along on the bottom book.</span>
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Two identical blocks, A and B, are on a horizontal surface, as shown above. There is negligible friction between the surface and
e-lub [12.9K]

Answer:

  the speed of the center of mass stays the same

Explanation:

In a system with no energy loss, momentum is conserved if the mass remains constant. The system described has no change in mass, and energy loss is considered negligible. Hence the product of the total mass and the velocity of its center will be a constant. The center of mass stays the same speed.

6 0
3 years ago
Object A has a mass of 100 grams. Object B has a mass of 150 grams. They are both traveling at the same velocity. What can you c
Scilla [17]
-- Momentum is (mass) x (speed). 
Object B has 1.5 times as much momentum as Object A has.

-- Kinetic energy is (1/2) x (mass) x (speed) . 
Object B has 1.5 times as much kinetic energy as Object A has.

-- If they would both stop long enough to get on the scale,
Object B would weigh 1.5 times as much as Object A does.
8 0
2 years ago
a moving billiard ball collides with an identical stationary billiard ball in an elastic collision. after the collision, the sec
MArishka [77]

A billiard ball collides with a stationary identical billiard ball to make it move. If the collision is perfectly elastic, the first ball comes to rest after collision.

<h3>Why does the first ball comes to rest after collision ?</h3>

Let m be the mass of the two identical balls.  

u1 = velocity before the collision of ball 1

u2 = 0 = velocity of second ball that is at rest

v1 and v2 are the velocities of the balls after the collision.

From the conservation of momentum,

∴ mu1 + mu2 = mv1 + mv2

∴ mu1 = mv1 + mv2

∴ u1 = v1 + v2

In an elastic collision, the kinetic energy of the system before and after collision remains same.

\frac{1}{2}  mu_1^2+0=\frac{1}{2}  mv_1^2+\frac{1}{2}  mv_2^2

∴  \frac{1}{2}  m(v_1+v_2 )^2=\frac{1}{2} mv_1^2+\frac{1}{2}mv_2^2

∴ \frac{1}{2} mv_1^2+\frac{1}{2} mv_2^2+mv_1 v_2=\frac{1}{2}  mv_1^2+\frac{1}{2} mv_2^2

∴ mv₁v₂ = 0

  1. It is impossible for the mass to be zero.
  2. Because the second ball moves, velocity v2 cannot be zero.
  3. As a result, the velocity of the first ball, v1, is zero, indicating that it comes to rest after collision.
<h3>What is collision ?</h3>

An elastic collision is a collision between two bodies in which the total kinetic energy of the two bodies remains constant. There is no net transfer of kinetic energy into other forms such as heat, noise, or potential energy in an ideal, fully elastic collision.

Can learn more about elastic collision from brainly.com/question/12644900

#SPJ4

3 0
1 year ago
Based on the mass and speed data, which object will have the greatest amount of kinetic energy
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The objects will have to be listed
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Find the radius using the centripetal acceleration formula: acceleration = 6.6 x 10^6 m/s^2 velocity = 2,000 rev/s
aksik [14]

the radius is 231

Explanation:

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3 years ago
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