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Sati [7]
3 years ago
14

If a sound wave traveled from a solid to a liquid its speed would:.

Physics
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

increase

Please Give Brainliest!

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A chicken flaps off the roof of the henhouse with a velocity of 4.5 m/s north. The chicken lands 2.8 seconds later. If a hungry
katrin2010 [14]
I think that it might be B?
                                  Tell me if im wrong
8 0
3 years ago
All compounds are positively charged true or false
marshall27 [118]

Answer:

false

Explanation: all compounds are electrically neutral.

4 0
3 years ago
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Seasonal changes in water temperature tend to remain within a narrow range. This is opposed to air temperature, which tends to f
Serjik [45]

It is because of the high specific heat of water.

Specific heat is the amount of heat needed to change the temperature of unit mass of a substance by one degree.

Specific heat of water is 4.186 kJ/kg K and that of air is 1 kJ/kg K. Thus, a given amount of heat will cause more change in the temperature of air than that of water.

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3 years ago
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Of these nonmetals, which one is likely to be the least reactive?
umka21 [38]

Answer:

helium

Explanation:

8 0
4 years ago
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In a physics laboratory experiment, a coil with 250 turns enclosing an area of 10.5 cm2 is rotated during the time interval 3.10
olchik [2.2K]
I guess the problem is asking for the induced emf in the coil.

Faraday-Neumann-Lenz states that the induced emf in a coil is given by:
\epsilon = -N \frac{\Delta \Phi}{\Delta t}
where
N is the number of turns in the coil
\Delta \Phi is the variation of magnetic flux through the coil
\Delta t is the time interval

The coil is initially perpendicular to the Earth's magnetic field, so the initial flux through it is given by the product between the magnetic field strength and the area of the coil:
\Phi_i = BA=(5.30 \cdot 10^{-5}T)(10.5 \cdot 10^{-4} m^2)=5.57 \cdot 10^{-8} Wb
At the end of the time interval, the coil is parallel to the field, so the final flux is zero:
\Phi_f = 0

Therefore, we can calculate now the induced emf by using the first formula:
\epsilon = -N  \frac{\Delta \Phi}{\Delta t}=- (250)  \frac{5.57 \cdot 10^{-8} Wb - 0}{3.10 \cdot 10^{-2} s} = -4.5 \cdot 10^{-4} V
7 0
4 years ago
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