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weeeeeb [17]
2 years ago
8

A motorcycle is moving at 18 m/s when its brakes are applied, bringing the cycle to rest in 4.7 s. To the nearest meter, how far

does the motorcycle travel while coming to a stop?
Physics
1 answer:
morpeh [17]2 years ago
4 0

Answer:

the motorcycle travels 42.4 meters until it stops.

Explanation:

Vi= 18 m/s

Vf= 0 m/s

t= 4.7 sec

Vf= Vi - a*t

deceleration:

a= Vi/t

a= 18m/s  / 4.7 sec =>  a=-3.82 m/s²

x= Vi*t - (a * t²)/2

x= 42.4m

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Find the y-component of this
Alborosie

Answer:

-0.0789 m

Explanation:

Recall that the y-component comes associated with the sin(18.4) through the following trigonometric relationship:

y = 0.250 sin(-18.4) ≈ -0.0789 m

Notice it is negative since it is below the x-axis.

4 0
3 years ago
2in+3in+4in+4in+6in+7in calculate the area and perimeter of each shape
ololo11 [35]
Perimeter=26in

Area would be to multiply the units together
4 0
2 years ago
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In the process of photosynthesis, how do plants obtain the water, carbon dioxide, and energy they use for this process?
NNADVOKAT [17]

Answer:

They get it from the air and soil. They also take energy from the sun.

Explanation:

During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil.

3 0
2 years ago
A golfer imparts a speed of 30.3 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te
sergey [27]

<u>Answer:</u>

a) Time spend by ball in air = 4.368 seconds

b)   Longest hole that golfer can make = 93.59 meter

<u>Explanation:</u>

  Projectile motion has two types of motion Horizontal and Vertical motion.

Vertical motion:

         We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

         Considering upward vertical motion of projectile.

         In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g m/s^2 and final velocity = 0 m/s.

        0 = u sin θ - gt

         t = u sin θ/g

    Total time for vertical motion is two times time taken for upward vertical motion of projectile.

    So total travel time of projectile = 2u sin θ/g

Horizontal motion:

  We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

  In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 m/s^2 and time taken = 2u sin θ /g

 So range of projectile,  R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}

a) We have golf ball travels maximum distance, so range is maximum.

                 Maximum range is when, sin 2θ =1

                             =>  θ = 45⁰

    Now we have travel time of projectile, t =  2u sin θ/g  

          Initial velocity = 30.3 m/s and  θ = 45⁰

                     So time spend in air, t = \frac{2*30.3*sin45}{9.81} =4.368 seconds

 b) Longest hole that golfer can make = Range of projectile = \frac{u^2sin2\theta}{g}

      Longest hole that golfer can make = \frac{30.3^2sin(2*45)}{9.81}=93.59 meter

4 0
2 years ago
An archer pulls her bowstring back 0.396 m by exerting a force that increases uniformly from zero to 237 N. (a) What is the equi
tatyana61 [14]

Answer:

(a) The equivalent spring constant is 598.485 N/m

(b) The work done is 46.926 J

Explanation:

From Hooke's law of elasticity

K (spring constant) = F/e

F is the range of force exerted = 237 - 0 = 237 N

e is the extension of bowstring = 0.396 m

K = F/e = 237/0.396 = 598.485 N/m

Work done = 1/2 Fe = 1/2 × 237 × 0.396 = 46.926 J

6 0
3 years ago
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