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3 years ago

A block weighing 35 N is resting on a steel table (us = 0.40).

Physics

1 answer:

rosijanka [135]3 years ago

4 0

Answer: 14

Explanation:

Force(normal)*coefficient

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A tiger travels 3m/s^2 for 4.1s,what was its initial speed if it's final speed was 55k/h?

zaharov [31]

Acceleration a=3m/s^2
time t= 4.1seconds
Final velocity V= 55km/h
initial velocity U= ?
First convert V to m/s
36km/h=10m/s
55km/h= 55*10/36=15.28m/s
Using the formula V= U+at
U= V-at
U= 15.28-3*4.1=15.28-12.3=2.98m/s
Initial velocity U= 2.98m/s or 10.73km/h (Using the conversion rate 36km/h=10m/s)

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alexandr1967 [171]

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3 years ago

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A 2-lb slider is propelled upward at A along the fixed curved bar which lies in a vertical plane. If the slider is observed to h

timofeeve [1]

To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

$F_n = \frac{mv^2}{r}$

$N+mgcos\theta = \frac{mv^2}{r}$

Here,

Normal reaction of the ring is N and velocity of the ring is v

$N+mgcos\theta = \frac{mv^2}{r}$

$N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})$

$N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}$

$N = 1.374lb$

PART B) Acceleration

$F_t = ma_t$

$-mgsin\theta = ma_t$

$-W sin\theta = \frac{W}{g} a_t$

$-2Sin30\° = (\frac{2}{32.2})a_t$

$a_T = -16.10ft/s^2$

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

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3 years ago

What is glucose made of

tigry1 [53]

Glucose is a simple sugar.

Its chemical formula is C₆ H₁₂ O₆ .

That tells you that every glucose molecule is made of 6 atoms of carbon,
12 atoms of hydrogen, and 6 atoms of oxygen.

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3 years ago

We know the frequency range of certain sounds are: 400-560 Hz, what are the ranges of wavelength in meters when the signal trans

Ksivusya [100]

Answer:

Range of wavelength will be $5.35\times 10^5m$ to $7.5\times 10^5m$