Answer:
3.88 * 10^(-15) J
Explanation:
We know that the Potential energy of the electron at the beginning of its motion is equal to the Kinetic energy at the end of its motion, when it reaches the plates.
First, we get the potential and potential energy:
Electric potential = E * r
E = electric field
r = distance between plates
Potential = 2.2 * 10^6 * 0.011
= 2.42 * 10^4 V
The relationship between electric potential and potential energy is:
P. E. = q*V
q = charge of electron = 1.602 * 10^(-19) C
P. E. = 2.42 * 10^4 * 1.602 * 10^(-19)
P. E. = 3.88 * 10^(-15) J
Answer: Option B
The wavelength for a radio wave with a frequency of 2 × 10⁴ Hz is
1.5 × 10⁴ m.
Explanation:
Wavelength is the measure of distance between two successive crests or troughs in a standing wave. Also wavelength can be measured as the ratio of velocity of light to frequency. It is like this because wavelength is inversely proportional to the frequency.
As c = 3 × 10⁸ m/s and the frequency is 2 × 10⁴ Hz, then the wavelength will be
So, the wavelength for a radio wave with a frequency of 2 × 10⁴ Hz is
1.5 × 10⁴ m.
Answer:
D) Reduce the time interval during which the magnitude of the field increases.
Spring would be for someone living near 3 on earth
The electric potential energy of the pair of charges when the second charge is at point b is U at b = +7.3×10⁻⁸J.
Electric potential is the amount of work done in moving point charge from infinity to aspecific point.
Calculation of the electric potential energy:
Here the particle should be moved from the point at the time when the potential energy should be U a
The U b should be the change in the potential energy
W is work done.
(W at a )-(W at b) = U a - U b
U b = U a - (W at a )+(W at b)
So,
= 5.4 × 10⁻⁸J - ( -1.9×10⁻⁸ J)
= +7.3×10⁻⁸J.
Learn more about electric potential here:
brainly.com/question/24284560
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