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ikadub [295]
2 years ago
8

What are the steps of natural selection?

Chemistry
1 answer:
blagie [28]2 years ago
5 0

Answer:

The five steps involved in the process of natural selection are

Variation • Inheritance • Selection • Time • Adaptation

☆anvipatel77☆

•Expert•

Brainly Community Contributor

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I need help! Thanks!
Tems11 [23]

Answer:

C. As speed increases, kinetic energy increase exponentially

Explanation:

As you can see on the graph, the further right we move on the x-axis, the higher the values on the y-axis. This means that as one value increases, the other value also increases. The only answer choice that says this is C.

Hope this helps :)

4 0
3 years ago
Read 2 more answers
In medical imaging, radioactive substances are sometimes used to help "see" parts of the body.
Kaylis [27]
This is true as some parts cannot be checked but the radioactive substances can be used in x-rays
4 0
3 years ago
Ba(oh)2+H3po4+h2o how is it <br> balance ?
Igoryamba

Answer:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Explanation:

Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 3 atoms of Ba on the right side and 1atom on the left side. It can be balance by putting 3 in front of Ba(OH)2 as shown below:

3Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 2 atoms of P on the right side and 1atom on the left. It can be balance by putting 2 in front of H3PO4 as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + H2O

Now, there are a total of 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Now the equation is balanced as the numbers of the atoms of the different elements present on both sides are equal

4 0
3 years ago
WILL MARK BRAINIEST <br><br> Can someone please help me understand this?
Mila [183]

To convert from moles to grams you divide by the molar mass of the element. To convert from grams to moles you X by the molar mass element

5 0
3 years ago
In one sample of a compound of copper and oxygen, 3.12g of the compound contains 2.50g of copper and the remainder is oxygen. Ca
blsea [12.9K]

Answer:

% composition O = 19.9%

% composition Cu = 80.1%

Explanation:

Given data:

Total mass of compound = 3.12 g

Mass of copper = 2.50 g

Mass of oxygen = 3.12 - 2.50 = 0.62 g

% composition = ?

Solution:

Formula:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition Cu = (2.50 g / 3.12 g)×100

% composition Cu = 0.80 ×100

% composition Cu = 80.1%

For oxygen:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition O = (0.62 g / 3.12 g)×100

% composition O = 0.199 ×100

% composition O = 19.9%

5 0
3 years ago
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