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Airida [17]
3 years ago
14

A number is Multiplied by 3 and 5 is added. If one half of the new nummber is 16, what was the first number​

Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

Step-by-step explanation:

The original number is x.

The new number is 3x + 5.

We know that 0.5(3x + 5) = 16, so 3x + 5 = 32.

3x + 5 = 32, 3x = 27, x = 9.

Hence the original number is 9.

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explain how you can use a box-and-whisker plot to find the range of a data set. a. the range is the difference of the values of
Advocard [28]
C. The range is the difference of the value of the whiskers.
Remember: the range is the highest value subtract the lowest value.
4 0
3 years ago
Dr black is standing 13 feet from a streetlamp. The lamp is making his shadow 9 feet long. He estimates that the angle of elevat
natta225 [31]

Dr black is standing 13 feet from a streetlamp. The lamp is making his shadow 9 feet long. He estimates that the angle of elevation from the tip of his shadow to the top of the streetlamp is 50° to the nearest foot the streetlamp is about  26 feet tall.

I hope this helps!

4 0
3 years ago
Practice Writing Composite Functions Given: f(x) = x - 7 and h(x) = 2x + 3 Write the rule for h(f(x)).
Setler79 [48]

Answer:

<h2>h(f(x)) = 2x - 11</h2>

Step-by-step explanation:

f(x) = x - 7

h(x) = 2x + 3

To find h(f(x)) substitute f(x) into h(x) that's replace every x in h(x) by f(x)

That's

h(f(x)) = 2(x - 7) + 3

h(f(x)) = 2x - 14 + 3

We have the final answer as

<h3>h(f(x)) = 2x - 11</h3>

Hope this helps you

6 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
HELP ASAP! Which is the steepest slope?<br> A. -3 <br>B. 1 <br>C. 2 <br>D. -4​
olga55 [171]
Positive and negative doesn’t matter. Steepest slope is the smallest or largest number.
In this case D. -4
3 0
3 years ago
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