All categories

3 years ago

If f(x)=7x and g(x)=3x+1, find (fog)(x)

Mathematics

1 answer:

marissa [1.9K]3 years ago

4 0

Fg(x) = 7(3x+1)
= 21x + 7

You might be interested in

Use the function below to find F(2) F(x)=1/3•4^x A.)2 B.)4 C.)8/3 D.)16/3

inna [77]

Answer:

Step-by-step explanation:

The function $F(x) = \frac{1}{3}*4^x$ has value F(2) when x = 2 is substituted.

$F(x) = \frac{1}{3}*4^x\\F(2) = \frac{1}{3}*4^2\\F(2) = \frac{1}{3}*16\\F(2) = \frac{16}{3}$

7 0

2 years ago

Last questions, plz help

Goryan [66]

Answer:

9. $a_n=7+6n$

10. $a_n=a_{n-1}+7$

Step-by-step explanation:

9. Given the sequence

$13, 19, 25, ...$

In this sequence,

$a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...$

Note that

$a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,$

then the common difference in this sequence is $d=6$

You have

$a_1=13\\ \\d=6,$

then the explicit formula is

$a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n$

10. Given the sequence

$-10,-3, 4, 11, ...$

In this sequence,

$a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...$

Note that

$a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,$

then the common difference in this sequence is $d=7$

You have

$a_1=-10\\ \\d=7,$

then the recursive formula is

$a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7$

5 0

3 years ago

Help! Got it wrong after trying first time and need helppp !

finlep [7]

We are given the equation:

DA - 2qA = B³

Taking 'A' common on the LHS

A(D - 2q) = B³

Dividing both sides by (D - 2q)

A = B³ / (D - 2q)

5 0

2 years ago

Giving all my points. please please answer lol.

CaHeK987 [17]

Answer: 3x/1

Step by step:

3 0

2 years ago

Read 2 more answers

Need help asap!!!!!!!!!!!!!!!!!!!!

ololo11 [35]

Answer: 1/b^5 (D)

Step-by-step explanation:

Is this a UTHS course I'm seeing?

8 0

2 years ago

Read 2 more answers