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lawyer [7]
4 years ago
8

Which compound can undergo an addition reaction? 1?

Chemistry
1 answer:
S_A_V [24]4 years ago
3 0

Only 2. Addition reactions require double bonds to be broken and are a characteristic of compounds with double bonds like alkenes. The rest of the options have no double bonds as you can see the carbons have the formula of alkalies. The only alkene is 2 the other compounds can be seen to be alkanes because they fit the general formula of alkanes. Each carbon is saturated and has four single bonds.


Hope this helps!

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A.
Andru [333]

Answer:

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7 0
3 years ago
Pairs of liquids that will mix in all proportions are called ________ liquids. unsaturated polar liquids supersaturated saturate
yKpoI14uk [10]

Answer:

Pairs of liquids that will mix in all proportions are called a.) miscible liquids. An unsaturated solution has solute less than the maximum.

Explanation:

i hope this helps . MISCIBLE LIQUIDS

8 0
3 years ago
HELP ME PLEASE THIS IS TIMED
Dovator [93]

Answer:

a cold front

Explanation:

A warm front brings fog, but a cold front brings clouds that form from dry air. A warm front brings thunderstorms, but a cold front brings widespread snowfall.

6 0
4 years ago
Read 2 more answers
Determine the answer to the following equation with correct number of significant figures: (4.123 × 0.12) + 24.2 =
rewona [7]

The value of the given equation i.e. (4.123 × 0.12) + 24.2 is 24.7.

Given that,

  • The equation is (4.123 × 0.12) + 24.2.

According to the BODMAS rule, first, we have to multiply 4.123 with 0.12 after that add the 24.2 to the value that comes.

So,

= (4.123 × 0.12) + 24.2

= 0.49476 + 24.2

= 24.69

= 24.70

Therefore we can conclude that the value of the given equation i.e. (4.123 × 0.12) + 24.2 is 24.7.

Learn more: brainly.com/question/24169758

8 0
3 years ago
How many atoms are in a sample of carbon weighing 16 grams? Round your answer to two decimal places.
Gennadij [26K]

Answer:

d) 8.01 E23 atoms

Explanation:

  • mol ≡ 6.022 E23 atoms

∴ mass C = 16 g

∴ molar mass C = 12.0107 g/mol

⇒ mol C = (16 g)*(mol/12.0107 g) = 1.332 mol

⇒ atoms C = (1.332 mol)*(6.022 E23 atoms/mol)

⇒ atoms C = 8.02 E23 atoms

8 0
3 years ago
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