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3 years ago

What is the temperature when a solid begins to liquefy

Physics

1 answer:

MrRa [10]3 years ago

6 0

Answer:

Explanation:

The temperature is at its Melting Point - temperature at which a solid begins to liquefy.

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A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it

mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

$radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm$

$r = 0.145\ cm = 0.145\times 10^{-2}\ m$

Charge ,

$Q = 30.0\ pC=30\times 10^{-12}$

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

$V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}$

Where,

V= Electric potential,

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge

r = Radius

Substituting the values we get

$V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}$

$V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt$

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0

4 years ago

What energy transformation is involved in movement of muscles?

baherus [9]

muscles perform Potential->Kinetic->heat potential- energy that can be used and is stored for use kinetic - movement heat- a prime factor of any kinetic relative.

hope it helped

8 0

3 years ago

If you are looking for a substance that will easily dissolve in water, you should look for a substance with which properties?

olga nikolaevna [1]

If you are looking for a substance that will easily dissolve in water, you should look for a substance with which properties? it is b. high solubility

5 0

3 years ago

The vertical motion of mass A is defined by the relation x 5 10 sin 2t 1 15 cos 2t 1 100, where x and t are expressed in millime

nikklg [1K]

Explanation:

Given that,

The vertical motion of mass A is defined by the relation as :

$x=10\ sin2t+15\ cos2t+100$

At t = 1 s

$x=10\ sin2+15\ cos2+100$

x = 115.33 mm

(a) We know that,

Velocity, $v=\dfrac{dx}{dt}$

$v=\dfrac{d(10\ sin2t+15\ cos2t+100)}{dt}$

$v=20\ cos2t-30\ sin2t$

At t = 1 s

$v=20\ cos2-30\ sin2$

v = 18.94 mm/s

We know that,

Acceleration, $a=\dfrac{dv}{dt}$

$a=\dfrac{d(20\ cos2-30\ sin2)}{dt}$

$a=-40\ cos2t-60\ cos2t$

At t = 1 s

$v=-40\ cos2-60\ cos2$

$a=-99.93\ mm/s^2$

(b) For maximum velocity, $\dfrac{dv}{dt}=a=0$

$-40\ cos2t-60\ cos2t=0$

t = 45 seconds

For maximum acceleration, $\dfrac{da}{dt}=0$

$80\ sin2t+120\ cos2t=0$

t = 61.8 seconds

Hence, this is the required solution.

5 0

4 years ago

In the circuit diagram, what does the symbol made of two Long lines and two short lines with a positive and a negative sign at e

Licemer1 [7]

That symbol represents a source of DC, usually a battery.

The zig-zag line represents a resistor, and the two little circles
connected by a short line represent a switch in the closed position.,

8 0

3 years ago