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kow [346]
3 years ago
13

What is the temperature when a solid begins to liquefy

Physics
1 answer:
MrRa [10]3 years ago
6 0

Answer:

Explanation:

The temperature is at its Melting Point - <em>t</em><u><em>emperature at which a solid begins to liquefy. </em></u>

<u><em /></u>

<u><em>Got The Answer From Google</em></u>

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The diagram is an illustration of<br> NO LINKS
V125BC [204]

Answer:

A longitudinal wave

Explanation:

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3 years ago
What is it called when a reading is converted into computer language? computerizing surveying digitizing converting
disa [49]
Digitizing is the correct answer
3 0
3 years ago
HALP me!! This is a physics question.
emmasim [6.3K]
<h2>Answer:</h2>

<u>Distance covered is 6.9 meters</u>


<h2>Explanation:</h2>

Data given:

Work Done = 345 kJ = 345000 J

Force = 5 x 10 ^ 4 =  50000 N

Distance = ?


Solution:

As we know that

Work Done = Force applied x Distance covered

By arranging the equation we get

Work / Force = Distance covered

By putting the values

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4 0
3 years ago
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What’s the spinning in earths axis that causes day and night called
sleet_krkn [62]

Answer:

rotation

Explanation:

The spinning of the Earth on its axis from west to east is called rotation. Effects of the Earth’s rotation are: The rotation of the Earth causes the day and the night. … Due to rotation, winds and the ocean currents deflect to the right in the Northern Hemisphere and to the left in the Southern Hemisphere. doggo knows ctrl+c, ctrl+v.

7 0
2 years ago
A positive test charge q is released from rest at distance r away from a charge of +Q and a distance 2r away from a charge of +2
Svetradugi [14.3K]

Answer:

B. to the right

Explanation:

Given:

  • test charge +q
  • distance of the test charge from +Q, r
  • distance of test charge from +2Q, 2r

<u>Force on the test charge due to +Q:</u>

F_1=k.\frac{Q.q}{r^2}

<u>Force on the test charge due to +Q:</u>

F_2=k.\frac{2Q.q}{(2r)^2}

F_2=k.\frac{Q.q}{2r^2}

Since all the charges are positive here, so they will try to repel the test charge away. And the force due to charge +Q will be greater so initially the test charge will move rightwards away from the +Q charge.

3 0
3 years ago
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