Answer:
when a two bodies A and B are moving at an angle 180° with each other then the relative velocity is the sum of bodies the velocity .i.e,
when the bodies move the opposite direction
then their relative velocity is the sum of individual velocities.
1. If we increase the distance to twice it's original value, the light intensity is reduced by one-fourth, the light intensity would be:
I0/4
2. rms magnetic field is inversely proportional to distance, so the new rms magnetic field would be:
B0/2
3. average energy density is inversely proportional to the square of the distance, so the new average energy density is:
E0/4
Answer: Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter.
Explanation:
That's all of the planets if you need them. Hope this helps!
Answer:
11.23%
Explanation:
Lets take
Speed of man in still water =u= 1.73 m/s
Speed of flow of water = v=0.52 m/s
When swims in downward direction then speed of man = u + v
When swims in upward direction then speed of man = u - v
Lets time taken by man when he swims in downward direction is
and when he swims in downward direction is
Lets distance is d and it will be remain constant in both the case




Time taken in still water
2 d= t x 1.73
t=1.15 x d sec


total time in current = 0.82 +0.44 d=1.26 d sec
So the percentage time

Percentage time =11.32%
So it will take 11.32% more time as compare to still current.
Answer:
a)
b) north edge will rise up
Explanation:
torque on the coil is given as

where N is number of loop = 9 loops
i is current = 7.80 A
-B -earth magnetic field = 
A- area of circular coil


A =0.015 m2
PUTITNG ALL VALUE TO GET TORQUE


b) north edge will rise up