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cupoosta [38]
2 years ago
6

Please helppp

Physics
1 answer:
Y_Kistochka [10]2 years ago
6 0

Answer:

F = 17.3 kN

Explanation:

The normal force must support the weight of the car plus provide for the needed centripetal acceleration.

F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300

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List five rules of golf etiquette. Explain the correct stance, grip, orientation, and parts of a swing.
Verizon [17]
- keep you eyes on the ball, after you hit the ball you look up, you have to see the club hit the ball

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8 0
3 years ago
Read 2 more answers
Camera flashes charge a capacitor to high voltage by switching the current through an inductor on and off rapidly. In what time
Ber [7]

Answer:

The value is  \Delta  t = 4.0 *10^{-7} \  s

Explanation:

From the question we are told that

  The current is \Delta  I  = 0.100 \  A

  The  inductor  is L  =  2.0mH  =  2.0*10^{-3} \  H

  The voltage induced is  \epsilon   =  500 V

Generally the emf induced is mathematically represented as

      \epsilon =  L  *  \frac{\Delta I }{\Delta  t }

Here  \Delta  t is the time taken  

=>  \Delta  t =  \frac{L  * \Delta  I }{\epsilon }

=>  \Delta  t =  \frac{2*10^{-3}  * 0.100 }{500  }

=>  \Delta  t = 4.0 *10^{-7} \  s

8 0
3 years ago
A wall clock has a minute hand with a length of 0.55 m and an hour hand with a length of 0.26 m. Take the center of the clock as
Lemur [1.5K]

Answer:

The magnitude of the acceleration of the tip of the minute hand of the clock 1.675\times10^{-6}\ m/s^2.

Explanation:

Given that,

Length of minute hand = 0.55 m

Length of hour hand = 0.26 m

The time taken by the minute hand to complete one revelation is

T= 3600\ sec

We need to calculate the angular frequency

Using formula of angular frequency

\omega=\dfrac{2\pi}{T}

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Using formula of acceleration

a=r\omega^2

Put the value into the formula

a=0.55\times(0.001745)^2

a=1.675\times10^{-6}\ m/s^2

Hence, The magnitude of the acceleration of the tip of the minute hand of the clock 1.675\times10^{-6}\ m/s^2.

3 0
3 years ago
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