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grigory [225]
3 years ago
8

What are three areas of science that rely on physical science?

Physics
2 answers:
mamaluj [8]3 years ago
6 0

Answer : Physical sciences deals with the sciences that are concerned with the study of inanimate natural objects, which includes physics, chemistry, astronomy, and other related subjects.

There are many other areas of science which rely on the physical science, it is stated below;

a) Physics

b) Astronomy

c) Chemistry

d) Earth sciences.

yanalaym [24]3 years ago
5 0
"physical science" is a branch of science that is based on practical tests and explanations of the different phenomena. It is based on scientific evidence and tests/experiments.

Some of the branches that are based on physical science are:
1- Astronomy
2- Electronics
3- Engineering
4- Radiology
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Monochromatic light is incident on a metal surface, and electrons are ejected. If the intensity of the light increases, what wil
drek231 [11]

Answer:The rate of ejection of photoelectrons will increase

Explanation:

If the frequency of incident monochromatic light is held constant and its intensity is increased, the rate of ejection of photoelectrons from the metal surface increases with increase in intensity of the monochromatic light. More current flows due to more ejection of photoelectrons.

4 0
3 years ago
A 73.9 kg weight-watcher wishes to climb a
Tresset [83]

The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km

<h3>How to determine the energy. </h3>

1 food calorie = 103 calories

Therefore,

991 food calories = 991 × 103

991 food calories = 102073 calories

Multiply by 4.2 to express in joule (J)

991 food calories = 102073 × 4.2

991 food calories = 428706.6 J

<h3>How to determine the height </h3>
  • Energy (E) = 428706.6 J
  • Mass (m) = 73.9 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) =?

E = mgh

Divide both side by mg

h = E / mg

h = 428706.6 / (73.9 × 9.8)

h = 591.95 m

Divide by 1000 to express in km

h = 591.95 / 1000

h = 0.59 Km

Learn more about energy:

brainly.com/question/10703928

7 0
2 years ago
A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 27 ∘ above t
ycow [4]

Answer:

Explanation:

Applied force, F = 18 N

Coefficient of static friction, μs = 0.4

Coefficient of kinetic friction, μs = 0.3

θ = 27°

Let N be the normal reaction of the wall acting on the block and m be the mass of block.

Resolve the components of force F.

As the block is in the horizontal equilibrium, so

F Cos 27° = N

N = 18 Cos 27° = 16.04 N

As the block does not slide so it means that the syatic friction force acting on the block balances the downwards forces acting on the block .

The force of static friction is μs x N = 0.4 x 16.04 = 6.42 N   .... (1)

The vertically downward force acting on the block is mg - F Sin 27°

                                                      = mg - 18 Sin 27° = mg - 8.172    ... (2)

Now by equating the forces from equation (1) and (2), we get

mg - 8.172 = 6.42

mg = 14.592

m x 9.8 = 14.592

m = 1.49 kg

Thus, the mass of block is 1.5 kg.  

6 0
3 years ago
A ball rolls from x=3.85m to x=22.1m in 5 seconds. What was its average velocity
Vadim26 [7]

Answer:

Average Velocity = 3.65 m/s

Explanation:

Average Velocity  =\frac{Total   Displacement}{Total     Time} =\frac{22.1-3.85}{5}=\frac{18.25}{5}=3.65

3 0
2 years ago
How does momentum relate to impulse ?
fomenos

Answer:

C. Impulse = F*t=(m*a)*t= m*(a*t) = m*Dv= D(Momentum) (“D” here’s mean Delta so change in)

Explanation:

In fact, the impulse is equal to the change in momentum of an object.

Impulse is defined as the product between the force (F) and the time (t):

I=Ft

however, the force is defined as the product between mass (m) and acceleration (a):

F=ma\\I=(ma)t

But the product a (acceleration) times t (time) is equal to the change in velocity of the object:

I=m(at)=m \Delta v

And this is exactly the definition of change in momentum:

I = m\Delta v = \Delta p

5 0
3 years ago
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