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german
3 years ago
6

What is the electric potential v due to the nucleus of hydrogen at a distance of 5.292×10−11 m ?

Physics
1 answer:
viktelen [127]3 years ago
5 0

Answer: 27.21 V

Explanation:

The <u>electric potential</u> V_{E} due to a point charge is expressed as:

V_{E}=k\frac{q}{r}

Where:

k=9(10)^{9}\frac{Nm^{2}}{C^{2}} is the <u>electric constant</u>

q=1.6(10)^{-19}C is the <u>electric charge of the hydrogen nucleus</u>, which is positive

r=5.292(10)^{-11}m is the <u>distance</u>

Rewritting the equation with the known values:

V_{E}=9(10)^{9}\frac{Nm^{2}}{C^{2}}\frac{1.6(10)^{-19}C}{5.292(10)^{-11}m}

Finally:

V_{E}=27.21 V

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- are independent of electric charge

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Explanation:

The strong force is one of the 4 fundamental forces of nature. It is responsible for holding the nucleons (protons and neutrons) together into the nucleus of the atom.

In fact, the protons inside the nucleus of an atom experience a repulsive, electrostatic force between each other: if this force was not balanced, the protons will simply fly away from each other, and the nucleus would break apart, so no nucleus could exist.

The strong force acts to prevent this effect: the strong force is attractive at such short scales, and it holds the protons and the neutrons together. It is independent of the electric charge: in fact, it acts in the same way on protons and neutrons, being attractive in both cases. Also, the strong force acts only over very short distances, so it acts only inside the nucleus of an atom.

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