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Reil [10]
2 years ago
10

A police car is driving north with a siren making a frequency of 1038 hz. Moops is driving north behind the police car at 12 m/s

and hard a frequency of 959hz. How fast is the police car going?
Physics
1 answer:
Marianna [84]2 years ago
8 0

Answer:

The police car is moving at 41.24 m/s.

Explanation:

To find the speed of the police car we need to use the Doppler equation:

f = f_{0}(\frac{v + v_{r}}{v + v_{s}})      

Where:

v: is the speed of the sound = 343 m/s

v_{r}: is the speed of the receiver = 12 m/s

v_{s}: is the speed of the source =?

f: is the observed frequency = 959 Hz

f₀: is the emitted frequency = 1038 Hz          

Both terms are positive in the fraction because the velocity of the sound is in the opposite direction to both velocities of the police car and the other car.  

By solving the above equation for v_{s} we have:        

v_{s} = \frac{f_{0}(v + v_{r})}{f} - v = \frac{1038(343 + 12)}{959} - 343 = 41.24 m/s  

Therefore, the police car is moving at 41.24 m/s.

I hope it helps you!                  

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if a star is moving towards Earth, it appears to emit light that is shorter in wavelength compared to a source of light that isn't moving. Because shorter wavelengths correspond to a shift towards the blue end of the spectrum, this is called blue shift.

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8 0
2 years ago
The graph below represents the motion of four cars, labeled W, X, Y, and Z.
ycow [4]

Answer:

Answer is A

Explanation:

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6 0
3 years ago
The maximum allowable resistance for an underwater cable is one hundredth of an ohm per
Studentka2010 [4]

Answer:

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

Explanation:

The resistance of a wire can be given by the following formula:

R = \frac{\rho L}{A}\\\\A = \frac{\rho L}{R} = \frac{\rho}{\frac{R}{L} }

where,

A = smallest cross-sectional area = ?

ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm

\frac{R}{L} = resistance per unit length of wire = 0.001 Ω/m

Therefore,

A = \frac{1.54\ x\ 10^{-8}\ \Omega m}{0.001\ \Omega/m}

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Answer:

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Explanation:

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