Answer:
1 is ur answer
Explanation:
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Answer:
At pH 3.5:
Peptide A with pI 5.1 and peptide B with pI 8.5 will both bind to the anion-exchange column.
At pH 6.5:
Peptide A with pI 5.1 will bind to the cation-exchange column, while peptide B with pI 8.5 will bind to the anion-exchange column.
At pH 10.8:
Peptide A with pI 5.1 and peptide B with pI 8.5 will both bind to the cation-exchange column.
Explanation:
Ion-exchange column chromatography is used for separating proteins and other molecules in a solution based on differences in net charge. Negatively charged molecules bind to positively charged solid supports called the anion-exchange column, whereas, positively charged molecules bind to negatively charged solid supports known as cation-exchange column.
A peptide can acquire a net charge if the pH of the medium is either above or below its isoelectric point,pI. At pH above pI, the peptide acquires a net negative charge and can bind to a positive support. At pH above pI, the peptide acquires a net positive charge and can bind to a negative support. The greater the difference between pH and pI, the tighter the peptide will bind to the column.
At pH 3.5:
Peptide A with pI 5.1 and peptide B with pI 8.5 will both bind to the anion-exchange column.
At pH 6.5:
Peptide A with pI 5.1 will bind to the cation-exchange column, while peptide B with pI 8.5 will bind to the anion-exchange column.
At pH 10.8:
Peptide A with pI 5.1 and peptide B with pI 8.5 will both bind to the cation-exchange column.
Answer: C. Al yields
Explanation: Oxidation is a process in which loss of electrons take place and thus results in increase in oxidation number of the element.
Reduction is a process in which gain of electrons take place and thus results in decrease in oxidation number of the element.
Plantae, as trees and flowers are examples of plants.
Percentage yield tells the percentage ratio of actual to theoretical yield. The theoretical yield of iron(III) sulfate is 26.52 g.
<h3>What is a theoretical yield?</h3>
The theoretical yield is the product formation from the complete modification of the limiting reagent in a chemical reaction.
The balanced chemical reaction is shown as,
Moles of ferric phosphate is calculated as:
From the reaction,
Solving for X:
Calculating mass from moles:
Therefore, option A. 26.52 gm is the mass of iron(III) sulfate.
Learn more about theoretical yield here:
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