N oxidation number in N₂O = 1
S oxidation number in SO₂ = 4
S oxidation number in SO₃ = 6
P oxidation number in P₄O₆ = 3
Therefore, the Sulfur in SO₃ will not react with molecular oxygen as Sulfur is already using all of its valence electrons in bonding.
D. There must be oxygen added. 2 of them don't even have oxygen anywhere in the formula, and the 3rd loses oxygen, which is reduction.
I think is it the flask the bottle cause i had the same thing and i got it right idk maybe :)
