This problem is very vague since no other details are
given. However for the sake of calculation let us assume that the compound is
an ideal gas at STP.
So that the molar volume is: 1 mole = 22.4 L
<span>density = (44.01 g/mol) * (1 mol / 22.4 L) = 1.96 g/L =
1.96 kg/m^3</span>
Explanation:
covalent bond poor thermal conductivity
molecular compounds
metallic bond ductile
electron sea model
ionic bond crystalline
hard and brittle
Covalent compounds have the following properties:
- Gases and volatile liquids or low melting point solids
- Often insoluble in polar solvents
- Mainly non - conductors
- Have slow reactions
Metallic compounds:
- Have good malleability, ductility, electrical and thermal conductivity.
- A large sea of electron by jointly packed atoms.
- They are mostly in metals
- Accounts for the bulk of the physical properties displayed by metals
Ionic compounds:
- High melting and boiling point
- Soluble in polar liquids
- Conducts electricity in molten or aqueous forms.
- Mostly crystalline solids
- Usually hard and brittle
- Undergoes fast chemical reactions
learn more:
Covalent bonds brainly.com/question/5258547
Ionic bond brainly.com/question/6071838
#learnwithBrainly
Answer:
Rate of the reaction= 9.92× 10^-5 M² min-1
Explanation:
Using the equation of reaction
2N2O5 ⟶ 4NO2+O2
Rate = k[N2O5]²
From the question k= 6.2×10-4
[N2O5]= 0.4
Rate = 6.2×10-4[0.4]²= 9.92×10-5M² min-1
Answer:
Explanation:
250 cm^3 of 0.2 moldm-3 H2SO4 can be prepared from 150cm^3 of 1.0 moldm^-3 by dilution.
150cm^3 of the 1.0 moldm^-3 stock solution is measured out using a measuring cylinder and transferred into a 250 cm^3 standard volumetric flask and made up to mark. The resulting solution is now 250cm^3 of 0.2 moldm-3 H2SO4.
Answer:
A. 32.6 g/mol
Explanation:
First convert the volume of gas to moles using the ratio 1 mol / 22.4 L at STP.
0.070 L • (1 mol / 22.4 L) = 0.00313 mol
Now divide the grams of gas by the moles of gas:
0.102 g / 0.00313 mol = 32.6 g/mol