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abruzzese [7]
3 years ago
8

A scientist wants to create a drug that will kill cancer cells upon absorption in the intestines. In order for the drug to work

effectively, it must not be absorbed until it reaches the intestines. The scientist tests different acidities of compounds to determine which combination will keep the drug intact until it reaches the intestines. What part of the engineering process is the scientist engaged in?
Chemistry
2 answers:
Anarel [89]3 years ago
8 0
The testing of the acidities of the compounds to determine the combination that will keep the drug intact before it reaches the intestines is a part of EXPERIMENTATION process. The experimentation is done in order to prove or answer different queries that were raised during the hypothesis making. 
OlgaM077 [116]3 years ago
7 0

<u><em>make a plan</em></u> i

s the answer for my apex users

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D is a green crystalline solid that dissolves in water to give a very pale green solution addition of sodium hydroxide solution
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I think its iron(II) oxide

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What is the difference between potential and kinetic energy
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Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Fi
erastovalidia [21]

Answer:

The answer to your question is:

Explanation:

Data

carbon        7.3%          =     7.3g

hydrogen    4.5%         =      4.5g

oxygen       36.4%         =     36.4 g

nitrogen     31.8%         =     31.8 g

Now

For carbon

                    12 g --------------------1 mol

                    7.3 g     -------------     x

                       x = 7.3/12 = 0.608 mol

For hydrogen

                 1 g   --------------------  1 mol

                 4.5 g  ------------------    x

                   x = 4.5 mol

For oxygen

             16 g ------------------- 1 mol

             36.4 g ----------------    x

             x = 2.28 mol

For nitrogen

              14 g   ----------------   1 mol

              31.8 g ---------------    x

             x = 2.27 mol

Now divide by the lowest result, the is 0.608 from carbon

carbon              0.608/0.608 = 1

hydrogen           4.5/ 0.608 = 7.4

oxygen              2.28/0.608 = 3.75

nitrogen             2.27/0.608 = 3.73

Empirical formula = CH₇O₄N₄

     

6 0
3 years ago
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