All categories

3 years ago

Explain how electrons make up part of an atom’s volume, but not much of its mass.

1 answer:

6 0

It makes up much of its volume because they move around the nucleus, so much of a atoms volume is empty space where the electrons are moving. However it's mass is 1 over 1840 amu

You might be interested in

8. What was the original concentration in the BHL sample, if the dilution is 1:500 and the concentration 0.07 mg/ml

Yakvenalex [24]

Answer:

The original concentration is "35 mg/ml".

Explanation:

According to the question,

The solution is diluted,

= 1:50

The initial volume,

V1 = 1 ml

Final concentration,

= 0.07 mg

then,

The final volume,

V2 = 500 ml

As we know,

⇒ $V_1N_1=V_2N_2$

or,

⇒ $N_1=\frac{V_2N_2}{V_1}$

On substituting the values, we get

⇒ $=\frac{500\times 0.07}{1}$

⇒ $=\frac{35}{1}$

⇒ $=35 \ mg/ml$

4 0

3 years ago

In unicorns, a heterozygous would have a rainbow tail

babunello [35]

Answer:

B???????????????????????

6 0

3 years ago

Give the formulas for the following

zubka84 [21]

Li2O

Fe(NO3)3

Al2O3

CuCl2

ZnSO4

All you have to do here is make sure your charges are balanced when you write the compound. For example, Iron (III) has a +3 charge, and nitrate has a -1 charge. You need 3 nitrates to match that charge, hence Fe(NO3)3.

8 0

3 years ago

What is the [ H3O+] of a solution with pH = (8.50x10^0)? enter your answer in scientific notation and with three sig figs.

erastovalidia [21]

Answer:

[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter

Explanation:

The pH is calculated with the formula:

pH = -lg[H₃O⁺]

From here the concentration of hydronium ion (H₃O⁺) will be:

[H₃O⁺] = $10^{-pH}$

[H₃O⁺] = $10^{-8.5}$

[H₃O⁺] = 3.162 × 10⁻⁹ moles / liter

3 0

3 years ago

Read 2 more answers

CaC2(s) + 2H2O(l) --> Ca(OH)2(aq) + C2H2(g) In the reaction above, 0.5487 grams of calcium carbide are completely consumed to

jasenka [17]

Answer:

239.7mL

Explanation:

Using the general gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas constant (0.0821 Latm/molK)

T = temperature (K)

The balanced chemical equation in this question is as follows:

CaC2(s) + 2H2O(l) --> Ca(OH)2(aq) + C2H2(g)

From the equation, 1 mole of CaC2 produces 1 mole of ethylene gas, C2H2.

Using mole = mass/molar mass

Molar mass of CaC2 = 40 + 12(2)

= 40 + 24

= 64g/mol

mole = 0.5487/64

mole = 0.00857mol of CaC2

Hence, 0.00857mol of CaC2 produced 0.00857mol of C2H2

Based on the information provided, n = 0.00857mol, T = 43°C = 43 + 273 = 316K, p = 0.926 atm

PV = nRT

V = nRT/P

V = 0.00857 × 0.0821 × 316/0.926

V = 0.222/0.926

V = 0.2397L

In mL, volume = 0.2397 × 1000

= 239.7mL

3 0

3 years ago