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GarryVolchara [31]
3 years ago
13

Explain how electrons make up part of an atom’s volume, but not much of its mass.

Chemistry
1 answer:
Talja [164]3 years ago
6 0
It makes up much of its volume because they move around the nucleus, so much of a atoms volume is empty space where the electrons are moving. However it's mass is 1 over 1840 amu
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2. How many grams of Mercury are in 9 moles of Mercury?
natulia [17]

Answer:

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Explanation:

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3 0
3 years ago
Write a balanced net ionic equation for the reaction of aqueous solutions of baking soda (NaHCO3) and acetic acid.(A) HCO3–(aq)
IgorC [24]

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium bicarbonate and acetic acid is given as:

NaHCO_3(aq.)+CH_3COOH(aq.)\rightarrow CH_3COONa(aq.)+H_2O(l)+CO_2(g)

Ionic form of the above equation follows:

Na^+(aq.)+HCO_3^-(aq.)+CH_3COO^-(aq.)+H^+(aq.)\rightarrow CH_3COO^-(aq.)+Na^+(aq.)+H_2O(l)+CO_2(g)

As, sodium and acetate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

HCO_3^-(aq.)+H^+(aq.)\rightarrow CO_2(g)+H_2O(l)

Hence, the correct answer is Option C.

8 0
3 years ago
A 312 g sample of a metal is heated to 257.128 °C and plunged into 200 g of water at a temperature of 41.933 °C. The final tempe
DENIUS [597]
<h3>Answer:</h3>

0.362 J/g °C

<h3>Explanation:</h3>

We are given:

Mass of metal = 312 g

Initial temperature of the metal = 257.128 °C

Mass of water = 200 g

Initial temperature = 41.933 °C

Final temperature of water = 67.555 °C

Specific heat capacity of water = 4.184 J/g °C

We are required to calculate the specific heat capacity of the metal;

Step 1: Heat gained by water

Quantity of heat = mass × specific heat × change in temperature

Q=m × c × Δt

Change in temperature, Δt = 25.622 °C

Therefore,

Heat gained by water = 200 g × 4.184 J/g °C × 25.622 °C

                                    = 21,440.49 Joules

<h3>Step 2: Heat released by the metal </h3>

Change in temperature of the metal, Δt =(257.128 °C-67.555 °C)

                                                                 = 189.573 °C

Q = mcΔt

Assuming the specific heat capacity of the metal is c

Q= 312 g × 189.573 °C × c

 = 59,146.776c Joules

<h3>Step 3: Calculate the specific heat capacity of the metal</h3>

The heat released by the metal is equivalent to heat gained by water.

Therefore;

59,146.776c J = 21,440.49 J

 c = 21,440.49 J ÷  59,146.776

    = 0.362 J/g °C

Thus, the specific heat capacity of the metal is 0.362 J/g °C

3 0
3 years ago
What is the mass percentage of JUST water in the hydrate CuSO4 ∙5H2O? The molar mass for the whole compound is 249.71 g/mol.
Black_prince [1.1K]

answer: 29x90=103

Kjjjj

7 0
3 years ago
What limitations are associated with the use of both<br> word and formula equations?
Dennis_Churaev [7]

Limitations of word equation and formula equation is that they do not express the quantities of reactant and product in the reaction.

Explanation:

Word equation expresses the chemical reaction in words. The reactants products and the direction of the reaction is mentioned in it. The information is used to write a chemical reaction. The word "reacted' shows the reactants and 'forms' show product. The sequence of reactions, moles of reactant and product is written.

Limitations:

Rate of reaction cannot be known.

Actual amount of product formed cannot be known.

eg: Addition of sodium oxide with water produces sodium hydroxide.

In formula equation symbols for element representation are used. The ratio of the elements in the reaction are also there. The atom numbers are indicated by the subscript number.

Limitations:

Concentration of both reactants and products is not mentioned.

The physical conditions of the reactants are not told

The thermodynamic conditions are not expressed as rate of reaction, pressure and temperature requirement.

Time taken to complete the reaction cannot be known.

Reaction mechanism cannot be observed by only chemical equations.

Value of actual yield is not given.

5 0
4 years ago
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