2 H₂O₂ --> 2 H₂ + 2 O₂
2 moles H₂O₂ ------> 2 moles O₂
8 moles H₂O₂ ------> ?
moles O₂ = 8 x 2 / 2
moles O₂ = 16 / 2
= 8 moles
Answer C
hope this helps!
Answer:
Sodium
(Na)
Just count the electrons and search which atom it is.
Answer:
When a sodium atom transfers an electron to a chlorine atom, forming a sodium cation (Na+) and a chloride anion (Cl-), both ions have complete valence shells, and are energetically more stable. The reaction is extremely exothermic, producing a bright yellow light and a great deal of heat energy.
Answer:
68.3%
Explanation:
First, let us look at the equation of reaction involving silver and magnesium chloride:
2Ag + MgCl2 ----> 2AgCl + Mg
1 mole of MgCl2 is required to precipitate 2 moles of Ag completely from the solution. That is a ratio of 1 to 2.
Now, mole of MgCl2 used to precipitate all the Ag
= molarity x volume
= 2.19 M x 2.89/1000
= 0.0063291 mole
Since 1 mole of MgCl2 would always require 2 moles of Ag, 0.0063291 mole will therefore require:
0.0063291 x 2 = 0.0126 mole of Ag
This means that 0.0126 mole of Ag is present in stephanie.
Mass of silver in stephanie = mole x molar mass
= 0.0126 x 107.8682
= 1.365 g
Thus, 1.365 g of silver is present in 2.00 g sample of stephanie.
Mass percent of silver in stephanie = 1.365/2.00 x 100
= 68.25% = 68.3% to the correct number of significant figure.
Answer:
60.0mL
Explanation:
For the process of titration , the formula we use is -
M₁V₁ = M₂V₂
Where ,
M₁ = initial concentration
V₁ = initial volume
M₂ = final concentration
V₂ = final volume .
Hence , from the question ,
The given data is ,
M₁ = 0.050 M
V₁ = 30.0mL
M₂ = 0.025 M
V₂ = ?
Now, to determine the unknown quantity , the formula can be applied ,
Hence ,
M₁V₁ = M₂V₂
Putting the respective values ,
0.050 M * 30.0mL = 0.025 M * ?
solving the above equation ,
V₂ = ? = 60.0mL
