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agasfer [191]
3 years ago
12

What is Will Ferrell’s middle name?

Chemistry
1 answer:
Vsevolod [243]3 years ago
6 0
William is the answer. Hope this helps and mark me brainliest!
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The chemical properties of calcium and strontium are similar because both
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Answer:

Number of valence electrons

Explanation:

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3 years ago
Determine the mass of 5.20 moles of c6h12
Gwar [14]
Mass is equal to moles x molar mass, and the molar mass of C6H12 is 84, therefore the mass is 436.8 g, but 437 rounded to correct significant figures
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Explain why either liquids nor gases have permanent shapes
Kruka [31]
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3 years ago
Is the electrochemical cell spontaneous or not spontaneous as written at 25 ∘C ? spontaneous not spontaneous Calculate the poten
givi [52]

Answer:

The cell potential is 0.609 V. Given E > 0 the electrochemical cell is spontaneous as written.

Explanation:

Let's consider the oxidation and reduction half-reactions and the global reaction.

Anode (oxidation): Sn²⁺(0.0023 M) ⇒ Sn⁴⁺(0.13 M) + 2 e⁻

Cathode (reduction): 2 Fe³⁺(0.11 M) + 2 e⁻ ⇒ 2 Fe²⁺(0.0037 M)

Global reaction: Sn²⁺(0.0023 M) + 2 Fe³⁺(0.11 M) ⇒ Sn⁴⁺(0.13 M) + 2 Fe²⁺(0.0037 M)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red,cat - E°red,an

E° = 0.771 V - 0.154 V = 0.617 V

The Nernst equation allows us to calculate the cell potential (E) under the given conditions.

E=E\° -\frac{0.05916}{n} logQ\\E=E\° -\frac{0.05916}{n} log\frac{[Sn^{+4}].[Fe^{2+}]}{[Sn^{2+}].[Fe^{3+} ]} \\E=0.617V-\frac{0.05916}{2} log\frac{(0.13).(0.0037)}{(0.0023).(0.11)} \\E=0.609V

The cell potential is 0.609 V. Given E > 0 the electrochemical cell is spontaneous as written.

4 0
3 years ago
Which of the following decomposition reactions is/are correct?
qwelly [4]
<span>A) 2NaOH -> 2Na + O2 + H2
is not correct since Na is unstable

B) 2NaOH -> 2Na + H2O + 1/2O2
is not correct since Na is unstable

C) 2NaOH -> Na2O + H2O
is correct since N2O is stable

D) 2NaOH -> 2Na + H2O2
is not correct since Na is unstable</span>
7 0
3 years ago
Read 2 more answers
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