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Olenka [21]
4 years ago
11

Which material is most likely to be a base?

Chemistry
2 answers:
Goshia [24]4 years ago
3 0

Answer:

Cooffee

Explanation:

<em>the answer is coffee because coffee might be bitter</em>

Luba_88 [7]4 years ago
3 0

Answer:Coffee

Explanation:Water is neutral, while the other answers are mostly organic acids but salt water is neither acidic nor basic

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Select the formula for the following acid: Carbonic Acid
Nina [5.8K]

Answer: 106

Explanation:

Follow PEMDAS. 7x12 = 84

84 + 13 = 97

97 + 9 = 106

4 0
3 years ago
100 POINTS ANSWER FAST
Nana76 [90]
The answer is A because it has the most amount of speed, the plane has the same speed but doesn't tell you for what amount of time is the speed so what if the plane traveled 15 per 2 hours or 3 obviously the truck is going faster and it if said 15 miles per minute then it would obviously be the plane but since it doesn't specify then the truck would be you rmost likely answer

Hope this helps
5 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%2012.046%20%5Ctimes%20%7B10%7D%20%5E%7B25%7D%20" id="TexFormula1" title=" 12.046 \times {
jarptica [38.1K]
Do I need to solve 12.046 x 10^25 to get the answer
3 0
3 years ago
The half-life of thorium-227 is 18.72 days. How many days are required for three-fourths of a given amount to decay?
Pie
T½=18.72days
therefore t¾=18.72+½ of 18.72
we have 18.72+9.36=28.08days
7 0
3 years ago
Consider a simple reaction in which a reactant AA forms products: A→productsA→products What is the rate law if the reaction is z
levacccp [35]

Answer :

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Zero order reaction : There is no affect on the rate law.

First order reaction : The rate law becomes doubled.

Second order reaction : The rate law becomes quadrupled.

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given reaction is:

A\rightarrow Products

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Now we have to determine that if doubling of the concentration of A then the rate of reaction will be:

As we know that the zero order reaction does not depend on the concentration of reactant. So, there is no affect on the rate law.

As we know that the first order reaction depend on the concentration of reactant. So, the rate law becomes doubled.

As we know that the second order reaction depend on the concentration of reactant. So, the rate law becomes quadrupled.

5 0
4 years ago
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