Answer : Tension in the line = 936.7 N
Explanation :
It is given that,
Mass of student, m = 65 kg
The angle between slackline and horizontal, 
The two forces that acts are :
(i) Tension
(ii) Weight
So, from the figure it is clear that :
Hence, this is the required solution.
Answer:
A) G = m³/kg.s²
B) E = kg.m²/s²
Explanation:
A)
The given relation is:
F = Gm₁m₂/r²
where, the units of all variables are:
F = Force = kg.m/s²
m₁ = m₂ = mass = kg
r = distance = m
G = Gravitational Constant = ?
Therefore,
kg.m/s² = G(kg)(kg)/m²
(kg.m/s²)(m²/kg²) = G
<u>G = m³/kg.s²</u>
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B)
The given equation is:
E = mc²
where, the units of all variables are:
m = mass = kg
c = speed = m/s
E = Energy = ?
Therefore,
E = (kg)(m/s)²
<u>E = kg.m²/s²</u>
This is the correct answer, which is not present in any option.
To solve this problem it is necessary to apply the concepts related to Hooke's Law as well as Newton's second law.
By definition we know that Newton's second law is defined as
m = mass
a = Acceleration
By Hooke's law force is described as
Here,
k = Gravitational constant
x = Displacement
To develop this problem it is necessary to consider the two cases that give us concerning the elongation of the body.
The force to keep in balance must be preserved, so the force by the weight stipulated in Newton's second law and the force by Hooke's elongation are equal, so
So for state 1 we have that with 0.2kg there is an elongation of 9.5cm
For state 2 we have that with 1Kg there is an elongation of 12cm
We have two equations with two unknowns therefore solving for both,
In this way converting the units,
Therefore the spring constant is 313.6N/m
Answer:
initial velocity=12.31 m/s
Final speed= 16.234 m/s
Explanation:
Given Data
height=5.72 m
distance=13.30 m
To Find
Initial Speed=?
Solution
Use the following equation to determine the time of the stone is falling.
d = vi ×t ½ ×9.8 × t²
Where
d = 5.72m and vi = 0 m/s
so
5.72 = ½× 9.8 ×t²
t = √(5.72 ÷ 4.9)
t=1.08 seconds
To determine the initial horizontal velocity use the following equation.
d = v×t
13.30 = v ×1.08
v = 13.30 ÷ 1.08
v=12.31 m/s
To determine stone’s final vertical velocity use the following equation
vf = vi+9.8×t............vi=0 m/s
vf = 9.8×1.08
vf= 10.584 m/s
To determine stone’s final speed use the following equation
Final speed = √[Horizontal velocity²+Final vertical velocity²]
Final speed = √{(12.31 m/s)²+(10.584 m/s)²}
Final speed= 16.234 m/s
