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s344n2d4d5 [400]
3 years ago
6

A basketball rolls to a stop along a gym floor without anyone touching it. What answer choice BEST explains why this occurred?

Physics
2 answers:
Minchanka [31]3 years ago
7 0
Frictional forces are exerting force against the basketball, causing it to stop.
salantis [7]3 years ago
5 0

its B,The opposing force of friction stopped the ball.

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A jet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. What is the radius of curvature of th
Gnoma [55]

Answer:

91.84 m/s²

Explanation:

velocity, v = 600 m/s

acceleration, a = 4 g = 4 x 9.8 = 39.2 m/s^2

Let the radius of the loop is r.

he experiences a centripetal force.

centripetal acceleration,

a = v² / r

39.2 x r = 600 x 600

r = 3600 / 39.2

r = 91.84 m/s²

Thus, the radius of the loop is 91.84 m/s².

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The__ of friction is a number that represents the resistance to sliding
Tresset [83]

Answer:

B. coefficient

Explanation:

i dont have to explain right?

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A certain wave motion has a frequency of 10 cycles / s and a wavelength of 3 m. so its propagation speed is
kodGreya [7K]
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What did Bohr’s model of the atom include that Rutherford’s model did not have?
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Bohr explained that the electron revolve around a orbit of fixed energy level that Rutherford fails to explain !!!
8 0
3 years ago
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A spotlight on the ground shines on a wall 12 meters away. If a man 2 meters high walks away from the spotlight towards the wall
nordsb [41]

Answer: The length of the shadow on the wall is decreasing by 0.6m/s

Explanation:

the specified moment in the problem, the man is standing at point D with his head at point E.

At that moment, his shadow on the wall is y=BC.

The two right triangles ΔABC and ΔADE are similar triangles. As such, their corresponding sides have equal ratios:

ADAB=DEBC

8/12=2/y,∴y=3 meters

If we consider the distance of the man from the building as x then the distance from the spotlight to the man is 12−x.

(12−x) /12=2/y

1− (1 /12x )=2 × 1/y

Let's take derivatives of both sides:

−1 / 12dx = −2 × 1 / y^2 dy

Let's divide both sides by dt:

−1/12⋅dx/dt=−2/y^2⋅dy/dt

At the specified moment:

dxdt=1.6 m/s

y=3

Let's plug them in:

−1/121.6) = - 2/9 × dy/dt

dy/dt = 1.6/12 ÷ 2/9

dy/dt = 1.6/12 × 9/2

dy/dt = 14.4/24 = 0.6m/s

5 0
3 years ago
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