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Ira Lisetskai [31]
3 years ago
5

A binary compound created by reaction of bismuth and an unknown element E contains 52.07% Bi and 47.93% E by mass. If the formul

a of the compound is Bi2E3, calculate the atomic mass of E.
Chemistry
1 answer:
yulyashka [42]3 years ago
6 0

Answer:

Atomic mass of E is 128.24

Explanation:

  • The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
  • In this case; the compound Bi₂E₃

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

            = (47.93 × 417.96 ) ÷ 52.07 %

            = 384.729

         E₃ = 384.729

Therefore; E = 384.729 ÷ 3

                     = 128.24  

The atomic mass of E is 128.24

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2 years ago
gA scientist is trying to discover information about an unknown metal in a compound. The formula for the compound is believed to
Hitman42 [59]

Solution :

It is given that :

The formula of the compound = $XBr_3$

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1 mol of $XBr_3$ contains = 3 mol of Br

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$4.834 \times 10^{-2}$ mol of $Br^-$  contains $1.576 \times 10^{-2}$ mol of $XBr_3$

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Therefore, the $\text{molar mass}$ of $XBr_3$  $=\frac{\text{mass}}{\text{mol}}$

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                                                          = 298.4 g/mol

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Wavelength of the light is 2.9 × 10⁻⁷ m.

<u>Explanation:</u>

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