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Rina8888 [55]
3 years ago
10

In science, Bob learns that the energy of a wave is directly proportional to the square of the waves amplitude. If the energy of

a wave is 4 J, what should he predict as the amplitude of the wave? A) 1 J B) 2 J C) 4 J D) 8 J
Chemistry
2 answers:
spayn [35]3 years ago
6 0

Answer:

B) 2 J

Explanation:

2 J

Since E ∝ amplitude2 then as the amplitude is doubled the energy is quardrupled.

Plugging in to check

amplitude2=E

amplitude2=4

amplitude2

=

4

amplitude=

4

amplitude=2

Illusion [34]3 years ago
4 0
Jamuuj ExpertThe energy of a wave is directly proportional to the square of the waves amplitude. Therefore, E = A² where A is the amplitude. This therefore means when the amplitude of a wave is doubled the energy will be quadrupled, when the amplitude is tripled the energy increases by a nine fold and so on.Thus, in this case if the energy is 4J, then the amplitude will be  √4 = 2 .
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Explanation:

The given data is as follows.

          \Delta H = 286 kJ = 286 kJ \times \frac{1000 J}{1 kJ}

                            = 286000 J

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 S_{O_{2}} = 205 J/^{o}K

Hence, formula to calculate entropy change of the reaction is as follows.

          \Delta S_{rxn} = \sum \nu_{i}S_{i}_(products) - \sum \nu_{i}S_{i}_(reactants)

                     = [(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]

                    = [(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]

                    = 163.5 J/K

Therefore, formula to calculate electric work energy required is as follows.

             \Delta G_{rxn} = \Delta H_{rxn} - T \Delta S_{rxn}

                            = 286000 J - (163.5 J/K \times 298 K)

                            = 237.277 kJ

Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.

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