Question

a 200 kg ball is dropped from a height of 2m, bounces on a hard floor and rebounds to a height of 1.5m. What maximum force does the floor exert on the ball?

Answer 1

Correct question:a 200 g ball is dropped from a height of 2m, bounces on a hard floor and rebounds to a height of 1.5m. What maximum force does the floor exert on the ball?

The diagram of the question is in the attachment.

Answer:

Explanation:

V=√2gh

g-10m/s²

let u be initial velocity ad v be final velocity,

u=√2*10*2

u=6.324m/s

v=√2*10*1.5

v=5.477m/s

from the diagram

t=5ms=0.005s

$F=\frac{m(v-u)}{t}$

$F=\frac{0.2(5.477-6.324)}{0.005}$

F=-33.87N    (the negative shows direction)

From the diagram Fmax=2F

   Fmax= 2*33.87

=67.74N