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3 years ago

What are two things that the amount of gravitational force between two object depends on

2 answers:

4 0

The equation behind this question is:

g = (G*m*M) / (r^2)

g is the gravitational force
G is the Universal Gravitational Constant
M is the mass of one object
and m is the mass of the other constant
r is the distance between the two objects

Amiraneli [1.4K]3 years ago

3 0

1). the product of the two masses being gravitationally attracted to each other

2). the distance between their centers of mass

And that's IT. The gravitational force between them depends on
only those two things, nothing else.

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olga55 [171]

Force because it’s a barrier to velocity so calculating that makes sense

7 0

3 years ago

What is the height of a 2.00 kg object if its potential energy is 100 J?

lara31 [8.8K]

<u>Given that:</u>

height (h) = ?

mass (m) = 2 Kg ,

Potential energy (P.E.) = 100 J ;

We know that P.E = m × g × h

100 J = 2 × 9.81 × h

h = (100) ÷ (2 × 9.81)

7 0

3 years ago

Below is an "oracle" function. An oracle function is a function presented interactively. When you type in a t value, and press t

Bingel [31]

Answer:

The rate of change of height with respect to time is -10.64 feet/sec

Explanation:

Given that,

There are three lines, so you can calculate three different values of the function at one time.

The function f(t) represents the height in feet of a ball thrown into the air, t seconds after it has been thrown.

Given table is,

Time t = 0, 1, 1,02

Function is, $F(t)=-3.053113177191196\times10^{-18},6.000000000000134, 6.41760000000015$

We need to calculate the initial height of ball

Using equation of motion

$h=h_{0}+ut-\dfrac{1}{2}gt^2$

Where, h₀ = initial height

u = initial velocity

t = time

g = acceleration due to gravity

At t = 0,

Put the value into the formula

$-3.053113177191196\times10^{-18}=h_{0}+0-0$

$h_{0}=-3.053113177191196\times10^{-18}$

We need to calculate the height of ball at t = 1

Using equation of motion

$h_{1}=h_{0}+u_{0}t-\dfrac{1}{2}gt^2$

Put the value in the equation

$6.000000000000134=-3.053113177191196\times10^{-18}+u-\dfrac{1}{2}\times32$

$6.000000000000134+3.053113177191196\times10^{-18}+16=u_{0}$

$u_{0}=22\ feet/s$

Velocity is the rate of change of height with respect to time

So, velocity at 1.02 sec is given

We need to calculate the height

Using equation of motion

$h=ut-\dfrac{1}{2}gt^2$

On differentiating w.r.to t

$h'(t)=u-\dfrac{1}{2}g(2t)$

Put the value into the formula

$h'(t)=22-\times32\times(1.02)$

$h'(t)=-10.64\ feet/sec$

Hence, The rate of change of height with respect to time is -10.64 feet/sec.

4 0

3 years ago

If a much heavier stone rolled off the same cliff, would it hit the ground more quickly? explain

N76 [4]

No, the rate of gravity remains constant

8 0

3 years ago

Read 2 more answers

Electromagnetic waves differ from the other types of waves because they are

Ronch [10]

Correct answer choice is :

B) Able to travel through a vacuum.

Explanation:

Electromagnetic waves are applied to carry long/short/FM wavelength radio waves, and TV/telephone/wireless signals or services. They are also effective for transferring energy in the form of microwaves, infrared radiation, visible light, ultraviolet light, X-rays, and gamma rays. Electromagnetic waves change from mechanical waves in that they do not need a medium to generate. This means that electromagnetic waves can move not only in the air and solid matters but also in the void of space.

Read more on Brainly.com - brainly.com/question/1697984#readmore

4 0

3 years ago

Read 2 more answers