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rosijanka [135]
3 years ago
9

What are two things that the amount of gravitational force between two object depends on

Physics
2 answers:
sp2606 [1]3 years ago
4 0
The equation behind this question is:

g = (G*m*M) / (r^2)

g is the gravitational force
G is the Universal Gravitational Constant
M is the mass of one object
and m is the mass of the other constant
r is the distance between the two objects
Amiraneli [1.4K]3 years ago
3 0
1).  the product of the two masses being gravitationally attracted to each other

2).  the distance between their centers of mass

And that's IT.  The gravitational force between them depends on
only those two things, nothing else.
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Which option lists a form of kinetic energy followed by a form of potential
Artemon [7]

Answer:

D. Sound Energy, Magnetic energy

Explanation:

Sound energy is in motion, and Magnetic energy is about to be in motion.

6 0
3 years ago
If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforc
Allisa [31]

Answer:

the net force applied to the car is zero.

Explanation:

According to Newton's second law, the acceleration of an object (a) is directly proportional to the net force applied (F):

a=\frac{F}{m}

where m is the object's mass.

In this problem, the car is moving with constant velocity: this means that the acceleration is zero, a = 0. Therefore, according to the previous equation, the net force must also be zero: F = 0. So, the correct answer is

the net force applied to the car is zero.

3 0
3 years ago
Identify five common business uses for electronic spreadsheets
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For the answer to the question above
Forecasting how a business might do in the future. 
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4 0
3 years ago
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A skater extends her arms, holding a 2 kg mass in each hand. She is rotating about a vertical axis at a given rate. She brings h
Usimov [2.4K]

Explanation:

It is known that relation between torque and angular acceleration is as follows.

                    \tau = I \times \alpha

and,       I = \sum mr^{2}

So,      I_{1} = 2 kg \times (1 m)^{2} + 2 kg \times (1 m)^{2}

                       = 4 kg m^{2}

      \tau_{1} = 4 kg m^{2} \times \alpha_{1}

     \tau_{2} = I_{2} \alpha_{2}

So,      I_{2} = 2 kg \times (0.5 m)^{2} + 2 kg \times (0.5 m)^{2}

                     = 1 kg m^{2}

 as \tau_{2} = I_{2} \alpha_{2}

                   = 1 kg m^{2} \times \alpha_{2}        

Hence,     \tau_{1} = \tau_{2}

                  4 \alpha_{1} = \alpha_{2}

            \alpha_{1} = \frac{1}{4} \alpha_{2}

Thus, we can conclude that the new rotation is \frac{1}{4} times that of the first rotation rate.

8 0
3 years ago
____ is a type of circuit were there is a direct connection between two points in a circuit that aren't supposed to be directly
PtichkaEL [24]

Answer:

Short

Explanation:

I took the same test

7 0
3 years ago
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