Answer:
2.15
Explanation:
For this question, we have to remember the <u>pH formula</u>:
![pH~=~-Log[H_3O^+]](https://tex.z-dn.net/?f=pH~%3D~-Log%5BH_3O%5E%2B%5D)
By definition, the pH value is calculated when we do the -Log of the concentration of the <u>hydronium ions</u> (
). So, the next step is the calculation of the <u>concentration</u> of the hydronium ions. For this, we have to use the <u>molarity formula</u>:
We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:
With this value, now we can calculate the pH value:
![pH~=~-Log[0.00693~M]~=~2.15](https://tex.z-dn.net/?f=pH~%3D~-Log%5B0.00693~M%5D~%3D~2.15)
<u>The pH would be 2.15</u>
I hope it helps!
Molarmass of beryllium is 9.0
molar mass of silicon is 28.4
molar mass of calcium is 40.1
molar mass of rhodium is 103.
Answer:
A (H)
Explanation:
The key uptop shows all the red are non metal and "H: is pink
According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,
P</span>₁ / T₁ = P₂ / T₂ ----- (1)
Data Given;
P₁ = 1.5 atm
T₁ = 35 °C + 273 = 308 K
P₂ = ?
T₂ = 0 °C + 273 = 273 K
Solving Eq. 1 for P₂,
P₂ = P₁ T₂ / T₁
Putting values,
P₂ = (1.5 atm × 273 K) ÷ 308 K
P₂ = 1.32 atm
Result:
As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.
Answer:
979 atm
Explanation:
To calculate the osmotic pressure, you need to use the following equation:
π = <em>i </em>MRT
In this equation,
-----> π = osmotic pressure (atm)
-----><em> i</em> = van't Hoff's factor (number of dissolved ions)
-----> M = Molarity (M)
-----> R = Ideal Gas constant (0.08206 L*atm/mol*K)
-----> T = temperature (K)
When LiCl dissolves, it dissociates into two ions (Li⁺ and Cl⁻). Therefore, van't Hoff's factor is 2. Before plugging the given values into the equation, you need to convert Celsius to Kelvin.
<em>i </em>= 2 R = 0.08206 L*atm/mol*K
M = 20 M T = 25°C + 273.15 = 298.15 K
π = <em>i </em>MRT
π = (2)(20 M)(0.08206 L*atm/mol*K)(298.15 K)
π = 979 atm
