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kumpel [21]
3 years ago
14

What is the change in energy ?e of the hydrogen atom as the electron makes the transition from the n=3 energy level to the n=1 e

nergy level?
Chemistry
1 answer:
Contact [7]3 years ago
5 0
The change in energy is is  known as work-energy
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Listening to music on your headphones converts what energy to what energy
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6 0
3 years ago
How can I balance this equation? TELL ME HOW you did it and all the steps and you will be the brainliest.
lianna [129]

Answer:

3 CH3CH2OH + 4 H2CrO4 + 6 H2SO4 --> 3 CH3COOH + 2 Cr2(SO4)3 + 13 H2O

Explanation:

To balance, start of with the groups that are common on both sides of the reaction equation;

In this case, these are the SO4 groups treating them as single units;

There are 3 on the right side and 1 on the left side, so we put 3 in front of the H2SO4 to balance this first;

Next, deal with the Cr, there are 2 Cr on the right side and 1 on the other side, so we put a 2 in front of the H2CrO4 to balance that;

Thirdly, we notice the C are already balanced as there are 2 on each side so this is fine;

Lastly, we can deal with the O and H;

Bearing in mind the numbers that are in front of the molecules now from prior balancing, there are 9 O and 16 H on the left side and 3 O and 5 H on the right;

7 H2O on the right side would balance the O, but gives us 18 H, which is 2 too many H;

If we were to put 2 in front of the two organic molecules (the ones with C) on either side, we would balance the O by having 6 H2O, but this gives 2 fewer H than necessary;

In order for the H to balance, we need to have 13/2 (or 6.5) H2O, which means we need 3/2 (or 1.5) in front of each organic molecule;

Since, it is not sensible to have 13/2 water molecules or 3/2 organic molecules, we can just multiply everything by 2;

Thus we end up with:

3 CH3CH2OH + 4 H2CrO4 + 6 H2SO4 --> 3 CH3COOH + 2 Cr2(SO4)3 + 13 H2O

Rules of thumb:

- When there are common chemical groups (e.g. SO4) on both sides of a reaction equation, treat them as single units

- Start of with balancing these common groups

- Thereafter, balance the atoms that appear in only one reactant and one product

- Proceed to balance the atoms that appear in more than one reactant or product

- Typically, you should deal with the O and H last

4 0
3 years ago
How many grams are in 3.45 moles of CaCl2
Firdavs [7]

Answer:

Explanation:

First we find the Molecular weight of CaCl2

looking at the periodic table the MW of Ca is 40.078 and Cl is 35.453 and the ratio of ca to cl is 1:2 so we multiply cl by 2 which is 35.453*2=70.906

we add them together: 40.078 + 70.906 = 110.984 g/mol

now:

\frac{110.984 grams}{mol} * 3.45 mol

the mol cancels out and we left with 3.45 * 110.984 grams = 382.89 grams

6 0
3 years ago
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