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kumpel [21]
3 years ago
14

What is the change in energy ?e of the hydrogen atom as the electron makes the transition from the n=3 energy level to the n=1 e

nergy level?
Chemistry
1 answer:
Contact [7]3 years ago
5 0
The change in energy is is  known as work-energy
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What value of ℓℓ is not allowed for an electron in an n = 3 shell?
dlinn [17]
Every electron shell, designated by "n", has a specific number of electron subshells. The shell number has values equivalent to natural numbers (1, 2, 3, 4...), while the subshells are s, p, d and f.

The subshell that does not exist within the third shell (n = 3) is the f subshell. The energy of the f subshell is too high and cannot be accommodated in the third shell.
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3 years ago
What two quantities must be known to calculate the density of a sample of matter?
Tanya [424]
The answer is A, mass and volume.

The equation for density, <span>ρ,</span> is ρ = m/V. m is mass and V is volume.
7 0
2 years ago
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You combine 13 g of magnesium with 5 g of nitrogen to form a compound.
guapka [62]

Answer:

\large \boxed{28 \, \% }

Explanation:

magnesium  + nitrogen ⟶ Product

      13 g                5 g

Mass of product = 13 g + 5 g = 18 g

The product contains 5 g of nitrogen .

\text{Percent N} =  \dfrac{\text{5 g}}{\text{18 g}} \times \, 100\% =  \mathbf{28 \, \%}\\\text{The percent by mass of nitrogen is $\large \boxed{\mathbf{28 \, \% }}$}

7 0
3 years ago
How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?
Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid \rm H_2SO_4 is a diprotic acid. When one mole of \rm H_2SO_4 molecules dissolve in water, two moles of \rm H^{+} ions would be produced.

\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}.

On the other hand, sodium hydroxide \rm NaOH is a monoprotic base. When one mole of \rm NaOH formula units dissolve in water, only one mole of hydroxide ions \rm OH^{-} would be produced.

\rm NaOH \to Na^{+} + OH^{-}.

Note that \rm H^{+} and \rm OH^{-} react at a one-to-one ratio:

\rm H^{+} + OH^{-} \to H_2O.

As a result, it would take 2\; \rm mol of \rm OH^{-} to react with the \rm 2\; mol of \rm H^{+} that was released when 1\; \rm mol of \rm H_2SO_4 is dissolved in water. Since one mole of \rm NaOH formula units could produce only one mole of \rm OH^{-}, it would take \rm 2\; mol of \rm NaOH formula units to produce that 2\; \rm mol of \rm OH^{-} for reacting with 1\; \rm mol of \rm H_2SO_4.

3 0
3 years ago
In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because _____.
kodGreya [7K]

Answer:

the work input is depented on the work output

Explanation:

7 0
3 years ago
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