Question

Write the chemical symbols for three different atomic cations that all have 14 protons

Answer 1

The symbols for three different cations with 14 protons are Si²⁺, Si⁴⁺, and Si³⁺.

An element with 14 protons must be silicon, Si.

Its electron configuration is [Ne] 3s²3p², so it could lose up to four valence electrons.

The most likely cations are Si²⁺, Si⁴⁺, and Si³⁺ (or Si⁺).

Answer 2

Answer:

The cations are $Si^+,Si^{2+},Si^{3+}$

Explanation:

Atomic number = Number of protons present in the nucleus of an atom of the element

Number of protons =14

Atomic number of an element will be 14.

The name of the element with 14 atomic number is silicon. It has equal number of electrons. Since an atom is a neutral species.

After loosing electrons atom gain positive charge.

$[Si]=1s^22s^22p^63s^23p^2$

After losing an electron is becomes $Si^{+}$

$[Si^+]=1s^22s^22p^63s^23p^1$

After losing 2 electron is becomes $Si^{2+}$

$[Si^{2+}]=1s^22s^22p^63s^23p^0$

After losing 3 electron is becomes $Si^{3+}$

$[Si^{3+}]=1s^22s^22p^6$