Answer:
Pressure of the gas is greater than the vapor pressure, therefore all the solid will not sublime.
Explanation:
To solve this problem we use ideal gas equation.
PV =nRT
If Presure of the gas (P) is greater than vapor pressure (56.5 atm), all the solid will not sublime. But If P < 56.5 atm, all of it will sublime.
where;
P is pressure of the gas in atm
V is volume of gas in Litre
T is absolute temperature of the gas in Kelvin
n is number of gas moles
R is ideal gas constant or Boltzmann constant = 0.082057 L atm K⁻¹ mol⁻¹
Given T = 20 °C = 273 + 20 = 293K
Volume = 0.25L
n = Reacting mas (m)/Molar mass(M)
Molar mass of CO₂ = 12 + (16X2) = 12+32 = 44g/mol
Reacting mass = 10g
n = m/M ⇒ 10/44
n = 0.2273
PV =nRT ⇒ P = nRT/V
P = (0.2273X0.082057 X293)/0.25
P = 21.8596 atm
Therefore, since Pressure of the gas is greater than the vapor pressure, all the solid will not sublime.
Answer:
True
Explanation:
Measurements of how orbital speeds depend on distance from the center of our galaxy tell us that stars in the outskirts of the galaxy. True or False
stars in the outskirt orbit the galactic center
the object mean orbital speed depends only on the Earth's mass and the semi-major axis (half the longest diameter) of the object's orbit. worthy of note. the orbital speed changes depending on where in the orbit the object is. It will be greatest when closest to Earth and least when furthest from Earth.
Energy=mass*SHC*temp change
=100*0.9*75
=6750J
A person usually breathes an average of 13 pints of air every minute.
Lungs aren't the same size. To accommodate the heart, the right lung is larger than the left lung — for humans, that is.
Lungs float on water. ...
Lungs and tennis courts can be the same size. ...
Oxygen only plays a small part in breathing.
The buoyancy of an object is dictated by its density. So let us calculate for density, where:density = mass / volume
Calculate the volume first of a solid cube:volume = (6 cm)^3 = 216 cm^3 = 216 mL
Therefore density is:density = 270 g / 216 mLdensity = 1.25 g / mL
Therefore this object will float in the layer in which the density is more than 1.25 g / mL.
