All categories

3 years ago

Buoyant force acts in the opposite direction as the force of

Physics

1 answer:

Natalka [10]3 years ago

3 0

Buoyant force acts in the opposite direction as the force of

Gravity

You might be interested in

During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive

Alex

Answer:

616.223684211 N

Explanation:

$F_r$ = Resistive force on the wheel = 115 N

F = Force acting on sprocket

$r_2$ = Radius of sprocket = 4.75 cm

$r_1$ = Radius of wheel = 25 cm

Moment of inertia is given by

$I=mr_1^2\\\Rightarrow I=1.7\times 0.25^2\\\Rightarrow I=0.10625\ kgm^2$

Torque

$\tau=I\alpha\\\Rightarrow \tau=0.10625\times 4.9\\\Rightarrow \tau=0.520625\ Nm$

Torque is given by

$\tau=Fr_2-F_rr_1\\\Rightarrow F=\dfrac{\tau+F_rr_1}{r_2}\\\Rightarrow F=\dfrac{0.520625+115\times 0.25}{0.0475}\\\Rightarrow F=616.223684211\ N$

The force on the chain is 616.223684211 N

5 0

3 years ago

Contrast balanced and unbalanced forces.

Bogdan [553]

Answer:

Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force. ... Forces that cause a change in the motion of an object are unbalanced forces.

8 0

3 years ago

A 3.30-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.10 m down the incline in 1.60 s.(a) fi

AnnZ [28]

<span>Mass of the block m = 3.3kg Angle of the slide = 30 degrees Distance the block slides s = 2.10 m Time taken to slide t = 1.6 s Initially in rest condition so initial velocity u = 0. We have an equation for distance s = (u x t) + (1/2) x (a t^2) s = (0 x t) + (1/2) x (a x (1.6) ^2) => 2.10 = (1/2) x (a x2.56) 2.56a = 4.20 => a = 1.64 So the magnitude of the Acceleration a = 1.64 m/s^2</span>

8 0

3 years ago

At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level (b) is 60.0 dB.

grigory [225]

Given that,

At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.

To find,

The distance from the source would the sound level be one-fourth the sound level at 3.00 m.

Solution,

The intensity from a source is inversely proportional to the distance.

Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?

Using relation :

$\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m$

So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.

8 0

3 years ago

Subscribe to my channel

Troyanec [42]

Sure why not I'll sub your channel

3 0

3 years ago