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erastovalidia [21]
2 years ago
10

the trend for ionization energy is a general increase from left to right across a period. However phosphorus is found to have hi

gher first ionization energy value than sulfur. Explain this exception to the general trend in terms of electron arrangements and attraction/repulsion
Chemistry
1 answer:
dimaraw [331]2 years ago
4 0
Since phosphorus is in the 5th group it has the ability to gain or lose electrons
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Answer:

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Explanation:

pK_{a}=-logK_{a} , where K_{a} is the acid dissociation constant.

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Hence, (\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})

So, \frac{[F^{-}]}{[HF]} is larger

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3 years ago
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Answer:

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