Answer:
![r=25M^{-1}s^{-1}[A]^2](https://tex.z-dn.net/?f=r%3D25M%5E%7B-1%7Ds%5E%7B-1%7D%5BA%5D%5E2)
Explanation:
Hello there!
In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:
![r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}](https://tex.z-dn.net/?f=r%3Dk%5BA%5D%5En%5C%5C%5C%5C%5Cfrac%7Br_1%7D%7Br_2%7D%20%3D%5Cfrac%7Bk%5BA%5D_1%5En%7D%7Bk%5BA%5D_2%5En%7D)
Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:

Which means this reaction is second-order with respect to A. Finally, we calculate the rate constant by using n, [A] and r, to obtain:
![k=\frac{r}{[A]^n} =\frac{1.0M/s}{(0.2M)^2}\\\\k=25M^{-1}s^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7Br%7D%7B%5BA%5D%5En%7D%20%3D%5Cfrac%7B1.0M%2Fs%7D%7B%280.2M%29%5E2%7D%5C%5C%5C%5Ck%3D25M%5E%7B-1%7Ds%5E%7B-1%7D)
Thus, the rate law turns out to be:
![r=25M^{-1}s^{-1}[A]^2](https://tex.z-dn.net/?f=r%3D25M%5E%7B-1%7Ds%5E%7B-1%7D%5BA%5D%5E2)
Regards!
Tin to Fluorine mass ratios:
1) For compound A:
38.5/12.3
= 3.13
2) For compound B:
56.5/36.2
= 1.56
The lowest whole number mass ratio is 2. It cannot be 1 because it is less than that required for compound B.
The correct answer is this one: "The amount of energy before and after the explosion depends on the type of reaction." The energy involved in an explosion is that t<span>he amount of energy before and after the explosion depends on the type of reaction, how strong and how weak; how destructive or less destructive.</span>
Hello,
The answer should be "thermal energy".
Reason:
The answer is thermal energy because the heat from whatever source the person is energy is transferring heat to the chicken which is causing the chicken to cook therefore the answer is thermal (heat) energy.
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit