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erastovalidia [21]
3 years ago
10

the trend for ionization energy is a general increase from left to right across a period. However phosphorus is found to have hi

gher first ionization energy value than sulfur. Explain this exception to the general trend in terms of electron arrangements and attraction/repulsion
Chemistry
1 answer:
dimaraw [331]3 years ago
4 0
Since phosphorus is in the 5th group it has the ability to gain or lose electrons
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If I have 7.5 L of a gas in a piston at a pressure of 1.75 atm and compress the gas until its volume is 3.7 L, what will the new
Sergio [31]

Answer:

3.55atm

Explanation:

We will apply Boyle's law formula in solving this problem.

P1V1 = P2V2

And with values given in the question

P1=initial pressure of gas = 1.75atm

V1=initial volume of gas =7.5L

P2=final pressure of gas inside new piston in atm

V2=final volume of gas = 3.7L

We need to find the final pressure

From the equation, P1V1 = P2V2,

We make P2 subject

P2 = (P1V1) / V2

P2 = (1.75×7.5)/3.7

P2=3.55atm

Therefore, the new pressure inside the piston is 3.55atm

7 0
3 years ago
In an ecosystem, what do organisms and populations with similar needs compete<br>over?​
hram777 [196]

Answer:

In any ecosystem, organisms and populations with similar requirements for food, water, oxygen, or other resources may compete with each other for limited resources, access to which consequently constrains their growth and reproduction. Growth of organisms and population increases are limited by access to resources.

5 0
3 years ago
Please help me, I really need it, God Bless you &lt;3
gladu [14]

#1

\\ \sf\longmapsto {}^{88}_{38}Sr^{2+}

  • As 2 electrons are donated Hence the No of electrons =38-2=36

#2

\\ \sf\longmapsto {}^{51}_{23}V^{3+}

  • As 3 electrons donated the no of electrons=23-3=20

#3

\\ \sf\longmapsto {}^{55}_{26}Fe^{3+}

  • No of neutrons=55-26=29

#4

\\ \sf\longmapsto {}^{112}_{48}

  • As 2 electrons are donated no of electrons =48-2=46

#5

\\ \sf\longmapsto {}^{210}_{82}Pb^{2+}

  • No of neutrons=210-82=128
7 0
2 years ago
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
3 years ago
5. _______ with the largest atoms and the smallest number of valence electrons and _______ with the smallest atoms and the great
kogti [31]

We have to fill the gap

The correct answer is: Metals with the largest atoms and the smallest number of valence electrons and non-metals with the smallest atoms and the greatest number of valence electrons are the most reactive.

Reactivity of any species depends on ease of release or gain of electron. The species which can release electron easily from valence shell, the species is more reactive whereas the species which can accept electron to its valence shell easily is also more reactive.


7 0
3 years ago
Read 2 more answers
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