Answer:
Heat required to melt 42 g if ice is 13,860 J
Explanation:
The amount of heat required to melt grams of water at 0°C is given as follows;
The mass of the ice (water), m = 42 g
The latent heat of fusion of ice Δ
= 330 J/g
Therefore, heat required to melt 42 grams is given as follows;
Heat required to melt ice = Mass of the ice, m × The specific latent heat of fusion of the ice, Δ
Heat required to melt 42 g if ice = m × Δ = 42 g × 330 J/g = 13,860 J
Heat required to melt 42 g if ice = 13,860 J.
It can bond with another atom to gain 3 more valence electrons (-3)
Answer : The correct option is, (c) pyramidal
Explanation :
As we are given that a molecule in which the central atom forms three single bonds and has one lone pair that means the central metal atom has 3 bond pairs and 1 lone pair of electrons.
There are total 4 electron pairs. So, the hybridization will be 
and the electronic geometry of the molecule will be tetrahedral.
But as there are three atoms or bonds around the central atom and the fourth position occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be pyramidal.
Hence, correct option is, (c) pyramidal
Answer:
24+74+61+29+38+27+68+54= 375
then divide by the number of numbers in this case 8 so;
375/8= 46.875
<h2>that's the median
46.875</h2>
Explanation:
