In order from LEAST density to most in order
1 answer:
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Answer:
a. the maximum number of σ bonds that the atom can form is 4
b. the maximum number of p-p bonds that the atom can form is 2
Explanation:
Hybridization is the mixing of at least two nonequivalent orbitals, in this case, we have the mixing of one <em>s, 3 p </em> and <em> 2 d </em> orbitals. In hybridization the number of hybrid orbitals generated is equal to the number of pure atomic orbital, so we have 6 hybrid orbital.
The shape of this hybrid orbital is octahedral (look the attached image) , it has 4 orbital located in the plane and 2 orbital perpendicular to it.
This shape allows the formation of maximum 4 σ bond, because σ bonds are formed by orbitals overlapping end to end.
And maximum 2 p-p bonds, because p-p bonds are formed by sideways overlapping orbitals. The atom can form one with each one of the orbitals located perpendicular to the plane.
Answer:
SOCl2, Mg, CH3CHO, H3O^+
Explanation:
The reaction of the 2,2-dimethylpropan-1-ol with SOCl2 converts the alcohol to an alkyl halide. This now reacts with Mg metal to yield a Grignard reagent.
The Grignard reagent reacts with CH3CHO and acid to yield 4,4-dimethylpentan-2-ol as shown in the image attached to this answer.
