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notsponge [240]
3 years ago
7

Two coins are flipped. What is the probability that both of the coins land on heads up

Mathematics
2 answers:
Lisa [10]3 years ago
5 0

Answer:

50%

Step-by-step explanation:

amid [387]3 years ago
4 0

Answer:

0.25, 25%, or 1/4

Step-by-step explanation:

There are two possibilities for each coin: heads or tails. So the chance of getting heads for the first flip is 50%, or 1/2. To find the probability for both, you multiply 1/2*1/2 and get 1/4.

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The blueprint for a new swimming pool uses the scale 3/4
beks73 [17]

Answer:

3 in wide by 4.5 in long.

Step-by-step explanation:

3/4=0.75

I divided the given dimensions by two, so I could multiply .75 by the sets of twos instead of dividing 3/4 by two and multiplying that by 12 and 8.

.74 x 4 = 3

.75 x 6 = 4.5

7 0
4 years ago
How many coconuts were in the original pile
leonid [27]
25 coconuts were in the originalpile the first sailor gave one of them to the monkeys and took 1/3 of the 24th equals eight which left 16 the second sailor gave one to the monkey and took 1/3 of 15 then all three sailors took two more each
4 0
4 years ago
Sam is rolling a number cube with the numbers 1, 1, 2, 2, 3, and 3 printed on it.
Illusion [34]
Sam has the probability of 0 because hes only using 1 cube with 1 number on each side.
8 0
4 years ago
A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa
Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, the parameters are:

z = 2.575, n = 2000, \pi = 0.77

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
3 years ago
Three friends went to the movies. Each movie ticket cost $8.50. Each person ordered a drink for $4.75. Two friends also bought p
vfiekz [6]

Answer:

P = $7.00

Step-by-step explanation:

Movie tickets = $8.50

Drink = $4.75

Two friends also bought popcorn

Total spent by the group = $53.75

Given equation:

3(8.50 + 4.75) + 2p = 53.75

Where,

P = cost of one order of popcorn

3(8.50 + 4.75) + 2p = 53.75

25.50 + 14.25 + 2p = 53.75

39.75 + 2p = 53.75

2p = 53.75 - 39.75

2p = 14

p = 14 / 2

p = 7

p = $7.00

8 0
3 years ago
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