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ddd [48]
2 years ago
7

In the simulation, there are three balls on the floor. Drag each of them up off the floor, and then let go. See what happens to

the balls. In what way do the balls behave the same? In what way do they behave differently?
Physics
1 answer:
Vlad1618 [11]2 years ago
7 0

Answer:

I hope this helps and I'm not to late

A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.

Explanation:

you also can use paraphrase to help you reword bye bye!!

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a sprinter starts from rest and accelerates at a rate of 0.16 ms ^-2 over a distance of 50.0 meters . How fast is the athlete tr
vlada-n [284]

Answer:

Final velocity v = 4 m/s

Explanation:

Given:

Initial velocity u = 0 m/s

Acceleration a = 0.16 m/s²

Distance s = 50 m

Find:

Final velocity v

Computation:

Using; v² = u² + 2as

v² = (0)² + 2(0.16)(50)

v² = 16 m/s

v = 4 m/s

Final velocity v = 4 m/s

7 0
3 years ago
As you are cycling to the Q center one spring day, you pass the construction site at Gant and stop to watch a few minutes. A cra
Rama09 [41]

Answer:

30.63 m

Explanation:

Using y = ut + 1/2gt² where u = initial speed of block = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time of fall = 2.5 s and y = height of fall.

So, substituting the values of the variables into the equation, we have

y = ut + 1/2gt²

y = 0 m/s × 2.5 s + 1/2 × 9.8 m/s² × (2.5 s)²

y = 0 m + 4.9 m/s² × 6.25 s²

y = 0 m + 30.625 m

y = 30.625 m

y ≅ 30.63 m

So, the brick fell 30.63 m

7 0
3 years ago
How can a cyclist minimize friction as he or she rides? A. by increasing the weight of the bike B. by increasing the tread on hi
jek_recluse [69]
B I believe is the answer!

Hope this helps and have a great day!!!
6 0
2 years ago
Read 2 more answers
What is the momentum of a 1550kg car that is traveling 38.0 m/s?
konstantin123 [22]

Answer:

p = 58,900 kg m/s

Explanation:

p = m × v

p = 1,550 × 38.0

p = 58,900 kg m/s

5 0
2 years ago
A physics professor is pushed up a ramp inclined upward at 30.0° above the horizontal as she sits in her desk chair, which slide
11111nata11111 [884]

Answer:

V = 3.17 m/s

Explanation:

Given

Mass of the professor m = 85.0 kg

Angle of the ramp θ = 30.0°

Length travelled L = 2.50 m

Force applied F = 600 N

Initial Speed  u = 2.00 m/s

Solution

Work = Change in kinetic energy

F_{net}d = \frac{1}{2}mv^{2} - \frac{1}{2}mu^{2}\\\frac{2F_{net}d }{m} = v^{2} -u^{2}\\ v^{2} =\frac{2F_{net}d }{m} +u^{2}\\ v^{2} =\frac{2(600cos30 - 85\times 9.8 \times sin30) \times 2.5 }{85} +2.00^{2}\\ v^{2} = 10.066\\v = 3..17m/s

7 0
2 years ago
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