Answer:
Final velocity v = 4 m/s
Explanation:
Given:
Initial velocity u = 0 m/s
Acceleration a = 0.16 m/s²
Distance s = 50 m
Find:
Final velocity v
Computation:
Using; v² = u² + 2as
v² = (0)² + 2(0.16)(50)
v² = 16 m/s
v = 4 m/s
Final velocity v = 4 m/s
Answer:
30.63 m
Explanation:
Using y = ut + 1/2gt² where u = initial speed of block = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time of fall = 2.5 s and y = height of fall.
So, substituting the values of the variables into the equation, we have
y = ut + 1/2gt²
y = 0 m/s × 2.5 s + 1/2 × 9.8 m/s² × (2.5 s)²
y = 0 m + 4.9 m/s² × 6.25 s²
y = 0 m + 30.625 m
y = 30.625 m
y ≅ 30.63 m
So, the brick fell 30.63 m
B I believe is the answer!
Hope this helps and have a great day!!!
Answer:
V = 3.17 m/s
Explanation:
Given
Mass of the professor m = 85.0 kg
Angle of the ramp θ = 30.0°
Length travelled L = 2.50 m
Force applied F = 600 N
Initial Speed u = 2.00 m/s
Solution
Work = Change in kinetic energy
