1/Rt = 1/R1 + 1/R2 + 1/R3+ 1/R4+ 1/R5
1/Rt = 1/6+ 1/6+1/6+1/6+1/6
1/Rt = 5/6
Rt = 6/5
Rt = 1.2 ohm
so B is the answer
The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
<h3>What is the angular velocity of the propeller?</h3>
The angular velocity of the propeller in rad/s is given as follows:
1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.
b. The linear velocity, v = radius * angular velocity
Linear velocity, v = 2.25/2 * 136.1
v = 153.1 m/s
c. Centripetal acceleration, 

Centripetal acceleration in terms of g; 
Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.
Learn more about angular velocity and centripetal acceleration at: brainly.com/question/10703948
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Answer:
a) h = 8.02 10³ m b) yes
Explanation:
a) The pressure in a fluid is given by
P = ρ g h
The pressure in this case is the atmospheric pressure, 1.013 105 Pa, let's clear the height (h)
h = P / ρ g
h = 1.013 10⁵ / (1.29 9.8)
h = 8.02 10³ m
b) The height of Mount Everest is 8848 m
It is above this height, according to this model there would be no air to breathe
High task repitition, forceful exertions, repetitive or sustained awkward posture
The compass magnet aligns itself with the earths magnetic field.