Answer:
Part a)

Part b)
North of East
Explanation:
Speed of train towards East = 60 km/h
displacement towards East is given as

now it turns towards 50 degree East of North
so its distance is given as


then finally it moves towards west for 50 min

Now the total displacement of the train is given as



now total time duration of the motion is given as


now average velocity is given as


Part a)
magnitude of the average velocity is given as



Part b)
Direction of the velocity is given as


North of East
Answer:
15 m per second
900m per minute
54,000 per hour
Explanation:
60 divided by 4 to get per second then times 60 for per minutes
then times 60 to get per hour
Answer:
(D) 42.4N
Explanation:
Since the frame is at rest, the net force acting on it must be 0. There are three forces acting on it: the gravity and the opposing forces of the two cables.
Since the gravity is a vertical force, we are only interested in the vertical components of the remaining forces. The net force equation is
F_net = 0 = F_g -2 * F_y
The vertical force of one cable (using the information in the drawing) is:
F_y = 30N * sin 45 deg = 21.21N
Now the weight can be determined:
0 = F_g - 2 * F_y
F_g= 2 * F_y = 2 * 21.21N = 42.4N
The weight of the frame is about 42.4N.