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Lubov Fominskaja [6]
3 years ago
9

A frustum of cone is filled with ice cream such that the portion above the cone is a hemisphere. Define the variables di=1.25 in

., d0=2.25 in., h=2 in., and determine the volume of the ice cream.
Engineering
1 answer:
LekaFEV [45]3 years ago
4 0

Answer:

The volume of the ice cream is V =  13.9898 in^3

Explanation:

Given

di = 1.25 in

d0 = 2.25 in

h = 2 in

For the calculation

di = 1.25/2

d0 = 2.25/2

h = 2

>> Vcon = \pi * h/3 * (di^2+di*d0+d0^2);

>> Vcon = 5.0437

>> Vtop = 2 * \pi * d0^3;

>>Vtop = 8.9461

>> V = Vcon + Vtop

V =  13.9898 in^3

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We would like to measure the density (p) of an ideal gas. We know the ideal gas law provides p= , where P represents pressure, R
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Maximum Density= Pressure (max)/(R*Temperature (min))= 126900/(287.058*332)= 1.331

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cheers i hope this helps

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Find the differential and evaluate for the given x and dx: y=sin2xx,x=π,dx=0.25
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By applying the concepts of differential and derivative, the differential for y = (1/x) · sin 2x and evaluated at x = π and dx = 0.25 is equal to 1/2π.

<h3>How to determine the differential of a one-variable function</h3>

Differentials represent the <em>instantaneous</em> change of a variable. As the given function has only one variable, the differential can be found by using <em>ordinary</em> derivatives. It follows:

dy = y'(x) · dx     (1)

If we know that y = (1/x) · sin 2x, x = π and dx = 0.25, then the differential to be evaluated is:

y' = -\frac{1}{x^{2}}\cdot \sin 2x + \frac{2}{x}\cdot \cos 2x

y' = \frac{2\cdot x \cdot \cos 2x - \sin 2x}{x^{2}}

dy = \left(\frac{2\cdot x \cdot \cos 2x - \sin 2x}{x^{2}} \right)\cdot dx

dy = \left(\frac{2\pi \cdot \cos 2\pi -\sin 2\pi}{\pi^{2}} \right)\cdot (0.25)

dy = \frac{1}{2\pi}

By applying the concepts of differential and derivative, the differential for y = (1/x) · sin 2x and evaluated at x = π and dx = 0.25 is equal to 1/2π.

To learn more on differentials: brainly.com/question/24062595

#SPJ1

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