Answer:
William Shockley, Walter Houser Brattain and John Bardeen.
Explanation:
It was built in 1947 and they won the novel peace prize in 1956
Answer:
no need for that
Explanation:
they are not the same at all
9514 1404 393
Answer:
see attached
Explanation:
Assuming flow is uniform across the cross section of the artery, the mass flow rate is the product of the volumetric flow rate and the density.
(5 cm³/s)(1.06 g/cm³) = 5.3 g/s
If we assume the blood splits evenly at the bifurcation, then the downstream mass flow rate in each artery is half that:
(5.3 g/s)/2 = 2.65 g/s
__
The average velocity will be the ratio of volumetric flow rate to area. Upstream, that is ...
(5 cm³/s)/(π(0.25 cm)²) ≈ 25.5 cm/s
Downstream, we have half the volumetric flow and a smaller area.
(2.5 cm³/s)/(π(0.15 cm)²) ≈ 35.4 cm/s
Answer:
(b) Given the Weibull parameters of example 11-3, the factor by which the catalog rating must be increased if the reliability is to be increased from 0.9 to 0.99.
Equation 11-1: F*L^(1/3) = Constant
Weibull parameters of example 11-3: xo = 0.02 (theta-xo) = 4.439 b = 1.483
Explanation:
(a)The Catalog rating(C)
Bearing life:
Catalog rating:
From given equation bearing life equation,
we Dividing eqn (2) with (1)
The Catalog rating increased by factor of 1.26
(b) Reliability Increase from 0.9 to 0.99
Now calculating life adjustment factor for both value of reliability from Weibull parametres
Similarly
Now calculating bearing life for each value
Now using given ball bearing life equation and dividing each other similar to previous problem
Catalog rating increased by factor of 0.61
Answer:
1. Cast iron or aluminum
2. aluminum (first blank) iron(second blank)
3. aluminum
4. dry sleeve
5. Wet sleeve
6. matching operation that cuts a series of holes through the block for crankshaft bearing