Answer:
I would say do it at an even pace
Explanation:
Doing it a slow pace takes time quickly will probably not to good gor you and doing it at an irregular pace is just way to fast
Answer:
battery life in year = 9 years and 48 days
Explanation:
given data
Battery Ampere-hours = 1.5
Pulse voltage = 2 V
Pulse width = 1.5 m sec
Pulse time period = 1 sec
Electrode heart resistance = 150 Ω
Current drain on the battery = 1.25 µA
to find out
battery life in years
solution
we get first here duty cycle that is express as
duty cycle =
...............1
duty cycle = 1.5 × 
and applied voltage will be
applied voltage = duty energy × voltage ...........2
applied voltage = 1.5 ×
× 2
applied voltage = 3 mV
so current will be
current =
................3
current = 
current = 20 µA
so net current will be
net current = 20 - 1.25
net current = 18.75 µA
so battery life will be
battery life = 
battery life = 80000 hours
battery life in year = 
battery life in year = 9.13 years
battery life in year = 9 years and 48 days
Answer:
Define Variables and Use List methods to do the following
Explanation:
#<em>Conjoins two lists together</em>
all_names = male_names.union(female_names)
#<em>Finds the names that appear in both lists, just returns those</em>
neutral_names = male_names.intersection(female_names)
#<em>Returns names that are NOT in both lists</em>
specific_names = male_names.symmetric_difference(female_names)