All categories

3 years ago

Why do we write proton ions first before electron ions?

1 answer:

6 0

Atoms that lose electrons acquire a positive charge as a result because they are left with fewer negatively charged electrons to balance the positive charges of the protons in the nucleus. Positively charged ions are called cations.

Hope that hepls

You might be interested in

Multiply. Write the answer in simplest form. 1 3/10×1/8

kicyunya [14]

9514 1404 393

Answer:

13/80

Explanation:

The product is ...

(1 3/10)×(1/8) = (13/10)×(1/8) = (13×1)/(10×8) = 13/80

4 0

2 years ago

How do you make a robotic dog

fredd [130]

In order to create a robotic dog, you are needing the necessary parts to create Goddard from Jimmy nutreon boy genius

7 0

3 years ago

Read 2 more answers

Name five or more items that were and may still be made by blacksmith

IgorLugansk [536]

Tools, weapons, hardware, armor

8 0

3 years ago

A Carnot refrigeration cycle absorbs heat at -12 °C and rejects it at 40 °C. a)-Calculate the coefficient of performance of this

tresset_1 [31]

Answer:

a)COP=5.01

b) $W_{in}=2.998$ KW

c)COP=6.01

d) $Q_R=17.99 KW$

Explanation:

Given

$T_L$ = -12°C, $T_H$ =40°C

For refrigeration

We know that Carnot cycle is an ideal cycle that have all reversible process.

So COP of refrigeration is given as follows

$COP=\dfrac{T_L}{T_H-T_L}$ ,T in Kelvin.

$COP=\dfrac{261}{313-261}$

a)COP=5.01

Given that refrigeration effect= 15 KW

We know that $COP=\dfrac{RE}{W_{in}}$

RE is the refrigeration effect

5.01= $\dfrac{15}{W_{in}}$

b) $W_{in}=2.998$ KW

For heat pump

So COP of heat pump is given as follows

$COP=\dfrac{T_h}{T_H-T_L}$ ,T in Kelvin.

$COP=\dfrac{313}{313-261}$

c)COP=6.01

In heat pump

Heat rejection at high temperature=heat absorb at low temperature+work in put

$Q_R=Q_A+W_{in}$

Given that $Q_A=15$ KW

We know that $COP=\dfrac{Q_R}{W_{in}}$

$COP=\dfrac{Q_R}{Q_R-Q_A}$

$6.01=\dfrac{Q_R}{Q_R-15}$

d) $Q_R=17.99 KW$

5 0

3 years ago

A ceramic matrix composite contains internal flaws as large as 0.001 cm in length. The plane strain fracture toughness of the co

murzikaleks [220]

Since the applied stress required for failure due to crack propagation is still higher than 550 MPa, the ceramic is expected to fail due to overload and not because of the flaws

Explanation:

Plane -Strain Fracture toughness is calculated as

$k_{IC}$ = $f$ б $\sqrt{\pi a}$

F=geometry factor of the flaw

б=Stress applied

$k_{IC}$ =Fracture toughness

a=Flaw size

Given that

Internal Flaw,a=0.001cm

Fracture Toughness $k_{IC}$ =45MPa $\sqrt{m}$

Tensile Strength б=550 MPa

Geometry Factor, $f$ =1

Calculation

An internal Flaw i s 0.001 cm

2a=0.001cm

a=0

6 0

3 years ago

Why do we write proton ions first before electron ions? ​

Why do we write proton ions first before electron ions?