Ask question

Ask question

All categories

3 years ago

15

A large fraction of the thermal energy generated in the engine of a car is rejected to the air by the radiator through the circu

lating water. Should the radiator be analyzed as a closed system or an open system?

1 answer:

Rina8888 [55]3 years ago

5 0

Open system because there is mass (water) flowing through the system of interest (radiator)

You might be interested in

Select four items that an industrial engineer must obtain in order to practice in the field.

alex41 [277]

Answer:

Professional engineering license

Bachelor's degree

Computer science classes

job recommendations

3 0

2 years ago

Read 2 more answers

When we utilize a visualization on paper/screen, that visualization is limited to exploring: Group of answer choices Relationshi

Mila [183]

Answer:

As many variables as we can coherently communicate in 2 dimensions

Explanation:

Visualization is a descriptive analytical technique that enables people to see trends and dependencies of data with the aid of graphical information tools. Some of the examples of visualization techniques are pie charts, graphs, bar charts, maps, scatter plots, correlation matrices etc.

When we utilize a visualization on paper/screen, that visualization is limited to exploring as many variables as we can coherently communicate in 2-dimensions (2D).

6 0

3 years ago

A satellite is launched 600 km from the surface of the earth, with an initial velocity of 8333.3 m./s, acting parallel to the ta

Vikki [24]

Answer:

eccentrcity of orbit is 0.22

Explanation:

GIVEN DATA:

Initial velocity of satellite = 8333.3 m/s

distance from the sun is 600 km

radius of earth is 6378 km

as satellite is acting parallel to the earth therefore $\theta angle = 0$

and radial component of given velocity is zero

we have $h = r_o v_r_o = 6378+600 =6.97*10^6 m$

h = 6.97*10^6 *8333.3 = 58.08*10^9 m^2/s

we know that

$\frac{1}{r} =\frac{GM}{h^2} \times ( i + \epsilon cos\theta)$

$GM = gr^2 = 9.81*(6.37*10^6)^2 = 398*10^{12} m^3/s$

so

$\frac{1}{6.97*10^6} =\frac{398*10^{12}}{(58.08*10^9)^2} \times ( i + \epsilon cos0)$

solvingt for $\epsilon)$

$\epsilon = 0.22)$

therefore eccentrcity of orbit is 0.22

6 0

3 years ago

Many households in developing countries prepare food over indoor cook stoves with no ducting system to exhaust the combustion pr

lorasvet [3.4K]

Answer:

C = 0.22857 ng / m³

Explanation:

Let's solve this problem for part the total time in the kitchen is

t = 2h (60 min / 1h) = 120 min

The concentration (C) quantity of benzol pyrene is the initial quantity plus the quantity generated per area minus the quantity eliminated by the air flow. The amount removed can be calculated assuming that an amount of extra air that must be filled with the pollutant

amount generated

C = co + time_generation rate / (area_house + area_flow)

C = 0.2 + 0.01 120 / (40+ 2)

C = 0.22857 ng / m³

7 0

3 years ago

Write a script named dif.py. This script should prompt the user for the names of two text files and compare the contents of the

Ainat [17]

Answer:

1

Created on Nov 3, 2018 @author: ASLand

7import atexit

#Read, nanes of both files

Rrintll"Enter tvo files to be compared below

userliamel input ("Enter the nome of the first file: ")

userliame2 input("Enter the name of the second file: ")

ROpen each file

f1 - open(userNamel, r')

@17 f2 = opan(useriame 2, )

tread all the lines into a list

d1 f1.readlines ()

d2 f2.readlines()

re equivalent, print "Yes" else pri

oiterate, and conpare

#11

the

y

if dl == d2:

print("Yes")

atexit

elif for i in range(@, min(len (d1), len(d2))):

if di[i]!=d2[i]:

PCint("No")

print(d1[i])

pcint(d2[])

7 0

3 years ago