Answer:
A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released? (Disregard air resistance.)
Show step by step please.
Note: The answer is given it's should be 1000 m ??
This what i can up with so see what it is kid
Explanation:
jetliner is moving with speed 146 mi/h
now we will have
now if it moves with this speed for 1.5 s
so the displacement for above time
now the deceleration of jet is given as
now by kinematics
so total displacement is given as
so displacement will be 555.7 m
Given :
- Mass of block = 3.5 kg
- Weight of Block = 3.5 kgf
- Volume of water displaced when body is fully immersed = 1000 cm³
Answer:
For calculating Upthrust on block we will have to first find out Volume of block :
↪Volume of block = Volume of water displaced
↪ Volume of block = 1000 cm³ = 0.001 m³
<h2>________________</h2>
Now, <u>we will calculate the Upthrust on block</u>:
↪ Upthrust on block = Volume of block * Density of water * g
↪ Upthrust on block = 0.001 * 1000 * g
↪ Upthrust on block = 1 kgf
Methane
The many covalent bonds between the atoms in hydrocarbons store a great amount of energy, which releases when these molecules burn
