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pentagon [3]
3 years ago
10

Which chemical can be toxic to the cells of it’s not removed?

Physics
2 answers:
Zepler [3.9K]3 years ago
7 0
Oxygen and water are NECESSARY.

Carbon dioxide isn't toxic, but it doesn't help anything.

Glucose is weird. It's necessary for cells to make energy with, but if it's too slow getting into the cells and hangs around in the blood for too long, then it's toxic. This is exactly the problem in diabetes.
masya89 [10]3 years ago
5 0
Hey There,

Question: <span>Which chemical can be toxic to the cells of it’s not removed?

Answer: D. Carbon Dioxide

If This Helps May I Have Brainliest?</span>
You might be interested in
If you lift two loads up one story, how much work do you do compared to lifting just one load up one story?
Daniel [21]

Answer:a

Explanation:

We have to lift the load two loads up one story, so energy required is

let m be the mass of each load and h is the height of each story

Energy E_1=2\times m\times g\times \h

E_1=2mgh

Here energy gained is the potential energy which depends upon the datum(floor).

For lifting one load up one story

Energy required

E_2=mgh

thus E_2 is half of E_1

So option a is correct                                

6 0
3 years ago
In the graph above, what is the instantaneous speed of the object after the first five seconds?
alexdok [17]

Answer:

D) 25 m/s

Explanation:

In order to solve this problem we must use the following kinematics equation.

v_{f} =v_{i} +(a*t)\\

where:

Vf = final speed [m/s]

Vi = initial speed = 0

a = acceleration = 5[m/s^2]

t = time = 5[s]

After 5 seconds the acceleration is equal to 5 [m/s^2]

Now replacing the values in the equation:

Vf = 0 + (5*5)

Vf = 25[m/s]

8 0
2 years ago
What is displacement?​
ycow [4]

Answer:

Change in position of an object A vector quantity with unit of distance.

Explanation:

Where is the object going? Final - initial

5 0
3 years ago
A ball of plasticine is released from rest at height of 2.2 m above the ground. After touching the ground, the plasticine ball c
Anna35 [415]

The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²

The direction of the acceleration of the ball is downwards

The given parameters

initial velocity of the ball, u = 0

height above the ground, h = 2.2 m

time of motion of the ball, t = 96 ms = 0.096 s

The magnitude of the acceleration of the ball while coming to rest is calculated as;

let the downwards direction of the acceleration be positive

h = ut + 0.5 at^2\\\\h = 0 + 0.5at^2\\\\h = 0.5 at^2\\\\a = \frac{h}{0.5t^2} \\\\a = \frac{2.2}{0.5 \times 0.096^2} \\\\a = 477.43 \ m/s^2

The direction of the acceleration of the ball is downwards

Learn more here: brainly.com/question/15407740

4 0
2 years ago
Write a hypothesis about how the number of half-lives affects the number of radioactive atoms. Use the "if . . . then . . . beca
Roman55 [17]

Answer:

Explanation:

Answer:

Explanation:

The half life is the time taken for half of a radioactive substance to disintegrate.

The shorter the half life, the larger the decay constant and the faster the decay process.

For a very large half life, it would take a very long time for the radioactive nuclide to decay to half.

With each half life reached, a new set of daughter cell is formed. Atoms that have short half life would decay rapidly. Every radionuclide has its own characteristic half-life.

If the number of half-lives increases, then the number of radioactive atoms decreases, because approximately half of the atoms' nuclei decay with each half-life. With this observation, we can hypothesise and conduct experiment to support the assertion that as the number of half-lives increases then the number of radioactive atoms decreases.

8 0
3 years ago
Read 2 more answers
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