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pentagon [3]
3 years ago
10

Which chemical can be toxic to the cells of it’s not removed?

Physics
2 answers:
Zepler [3.9K]3 years ago
7 0
Oxygen and water are NECESSARY.

Carbon dioxide isn't toxic, but it doesn't help anything.

Glucose is weird. It's necessary for cells to make energy with, but if it's too slow getting into the cells and hangs around in the blood for too long, then it's toxic. This is exactly the problem in diabetes.
masya89 [10]3 years ago
5 0
Hey There,

Question: <span>Which chemical can be toxic to the cells of it’s not removed?

Answer: D. Carbon Dioxide

If This Helps May I Have Brainliest?</span>
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A wheel with radius 0.487 m rotates 5.75 times every second. find the period of this motion.
marin [14]
Calculate the circumference of the circular path of the wheel by the equation,
    C = 2πr
where C is the circumference,
           r is the radius

Substituting the known values,
    C = 2(π)(0.487 m) = 3.06 m

Then, period of the motion will be determined by dividing the number of rotations done,
 
     T = (3.06 m) / (5.75 /s) = 0.53 s

<em>ANSWER: 0.53 s</em>
3 0
3 years ago
What is umax,c, the value of the maximum energy stored in the capacitor during one cycle?
TiliK225 [7]

1) 0.266 H

2) 0.040 J

3) 0.308\Omega

Explanation:

The diagram of the circuit is missing: find it in attachment.

1) What is L, the value of the inductance of the circuit?

For an RLC circuit, the resonant angular frequency is given by:

\omega=\frac{1}{\sqrt{LC}}

where

L is the inductance of the circuit

C is the capacitance of the circuit

In this problem, we have:

\omega=164 rad/s is the angular frequency of the generator, at which the circuit is in resonance

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

Therefore, solving for L, we find the inductance of the circuit:

L=\frac{1}{\omega^2 C}=\frac{1}{(164)^2(140\cdot 10^{-6})}=0.266 H

2) What is umax,c, the value of the maximum energy stored in the capacitor during one cycle

The maximum energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance of the capacitor

V is the maximum potential difference across the capacitor

Here we have:

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

V=24 V is the maximum voltage across the capacitor, which is the emf of the generator

Substituting, we find:

U=\frac{1}{2}(140\cdot 10^{-6})(24)^2=0.040 J

3) What is R, the value of the resistance of the circuit?

Here we want to find the resistance of the circuit.

The resistance of the circuit can be found by using Ohm's Law:

V=RI

where

V is the maximum voltage

R is the resistance

I is the maximum current

Here we have:

V = 24 V is the maximum voltage provided by the generator

I = 0.78 A is the maximum current in the circuit

Solving for R, we find the resistance:

R=\frac{V}{I}=\frac{0.24}{0.78}=0.308\Omega

6 0
3 years ago
Workshop:The analysis of a simple pendulum assumed that the mass was a particle, with no size. A realistic pendulum is a small,
bagirrra123 [75]

Answer:

The expression for the period of the pendulum is

T=2π√l/g

Explanation

Kindly find attached document for the analysis of the pendulum and the derivation for the period

What is a simple harmonic motion?

Simple harmonic motion is defined as the to and fro motion of an object or a particle whose acceleration is directly proportional to its displacement from a fixed point and is always directed towards that point.

4 0
3 years ago
If the pitch of a sound decreases and the sound source is moving, is the sound source moving toward or away from the observer
fiasKO [112]
The sound source must be moving away
6 0
3 years ago
Mass m = 0.1 kg moves to the right with speed v = 0.31 m/s and collides with an equal mass initially at rest. After this inelast
nataly862011 [7]

Answer:

VR = 0.26 m/s

Explanation:

m = 0.1 kg                                M = 0.1 kg

v = 0.31 m/s                              Vi = 0 m/s    

the kinetic energy of the system initially is:

Ki = 1/2×m×(v^2) + 1/2×M×(Vi)^2

   = 1/2×(0.1)×(0.31)^2

   = 4.805×10^-3 J

then, we told that the system after collision only retains a fraction 0.69 of its initial kinetic energy. that is the final kinetic energy of the system is:

Kf = 0.69×4.805×10^-3 J

    = 3.31545×10^-3 J

but due equal masses of the bodies, we know that after the collision the only body that would be in motion would be the body that at res and the body that was initially moving will now be at rest.so the kinetic energy is only made by the second body and given by:

                   Kf = 1/2×M×(VR)^2

3.31545×10^-3 = 1/2×(0.1)×(VR)^2

               VR^2 =  0.066309

                   VR = 0.26 m/s

according to the coservation of linear momentum:

6 0
4 years ago
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