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Pepsi [2]
3 years ago
14

Use the X method to find the solutions of 6x2 + 2x – 20 = 0

Mathematics
2 answers:
SVEN [57.7K]3 years ago
5 0
The X method?
2x=8
X=4
Hunter-Best [27]3 years ago
3 0

Answer:

x= 4

Step-by-step explanation:

first move 20 so you add it

6 x 2 + 2x -20 =0

               +20  +20

6 x 2 + 2x =20

12 + 2x =20

-12         -12

2x = 8

div

x=4

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A company that accepts credit cards is charged $0.02 a transaction in
hjlf

this is money, it would <u>technically</u> be $574.20.

But we have to remember that, for your question, you also have a $0.02 Ah, precentages. <em>Gotta love 'em.</em>

<em />

Remember that when you want to find how much to take away from something (When you know the percentage that you need to take off), you have to move the decimal two spots to the left, meaning that 21% becomes .21, 4% becomes 0.04, and 112% becomes 1.12. A good way to remember this is by looking at the two dots on the percentage sign, and relating the two dots to the two spots you need to move the decimal by.

Knowing this we can now move on.

To find out how much to take away from something (E.G: 10% of 50 or 54% of 4300), we first need to move the decimal from our percentage. Once we've done that, we're almost ready. Now, we need to multiply <em>w</em> by <em>x</em> to get <em>y</em> and eventually get <em>z</em> (Where <em>w</em> is the number we need to take away from, <em>x</em> is the percentage after we had moved the decimal, and <em>y</em> is the number we need to subtract from <em>w</em> to get <em>z</em>, which is our number after the precentage has been taken out of it.

So,

<em>w</em> * <em>x</em> = <em>y</em> then <em>w</em> - <em>y</em> = <em>z</em>

580 * 0.01 = 5.8 then 580 - 5.8 = 574.2

But since this is money, remember that this can also be expressed as $574.20

<h2><u><em>BUT WAIT!!!!</em></u></h2><h3>We can't stop here, because we are trying to figure out how much gets added onto <u>the transaction</u>, <u><em>not</em></u> how much the transaction would be taxed <u>if</u> they were removed <em>y</em>.</h3>

Meaning, that the answer is actually 585.82, because 580 * 0.01 = 5.8 then 5.8 + 0.02 = 5.82 then  580 + 5.82 = 585.82 ($0.02 being the charge applied to every transaction.)

So, the answer should be $585.82

4 0
3 years ago
Calculate the perimeter of the square with side length of 10 ft.
Pavlova-9 [17]
Squares have all equal sides so 10x4=40 40 ft is the answer
5 0
3 years ago
40 POINTS AND BRAINLIEST
ladessa [460]

Answer:

120

Step-by-step explanation:

As x goes from 1 to 2, y increases by 4 from 4 to 8

As x goes from 2 to 3, y increases by 4 from 8 to 12

We increase by 4 each time

The formula for an arithmetic sequence is

an = a1+d(n-1)

where a1 is the first term which is 4

d is the common difference or the number we add each time which is 4

n is the term we are looking for which is 30

a30 = 4 +4 (30-1)

a30 = 4+4(29)

       = 4+116

      = 120

5 0
3 years ago
Read 2 more answers
30 POINTS + BRAINLIEST!
crimeas [40]
The secant tangent theorem states that the distance from (y to the tangent point x) squared = the external segment * length of the secant.
Put in plane English
YX^2 = YV * YZ
YV = 9
YZ = 9 + 19 = 28
YX^2 = 28 * 9
yX^2 = 252
YX = sqrt(252)
YX = 15.87
3 0
3 years ago
Read 2 more answers
Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

7 0
3 years ago
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