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3 years ago

12

the number of electrons in a copper penny is approximately 10 10^23. How large would the force be on an object if it carried thi

s charge and were repelled by an equal charge one meter away?

1 answer:

iVinArrow [24]3 years ago

8 0

Answer:

0.000230144 N

Explanation:

n = Number of electrons = $10\times 10^{23}$

q = Charge of electron = $1.6\times 10^{-19}\ C$

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

r = Distance between obects = 1 m

The force would be

$F=\dfrac{nkq^2}{r^2}\\\Rightarrow F=\dfrac{10\times 10^{23}\times 8.99\times 10^9\times (1.6\times 10^{-19})^2}{1^2}\\\Rightarrow F=0.000230144$

The force would be 0.000230144 N

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R = 0.407Ω.

The resistance R of a particular conductor is related to the resistivity ρ of the material by the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of the material.

To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.

We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4. Then:

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2 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A

ArbitrLikvidat [17]

Answer:

The mass of the solid cylinder is $m = 1612.5 \ kg$

Explanation:

From the question we are told that

The radius of the grinding wheel is $R = 0.330 \ m$

The tangential force is $F_t = 250 \ N$

The angular acceleration is $\alpha = 0.940 \ rad/s^2$

The torque experienced by the wheel is mathematically represented as

$\tau = I * \alpha$

Where I is the moment of inertia

The torque experienced by the wheel can also be mathematically represented as

$\tau = F_t * r$

substituting values

$\tau = 250 * 0.330$

$\tau = 82.5 \ N\cdot m$

So

$82.5 = I * \alpha$

$82.5 = I * 0.940$

So

$I = 87.8 \ kg \cdot m^2$

This moment of inertia can be mathematically evaluated as

$I = \frac{1}{2} * m* r^2$

substituting values

$87.8 = \frac{1}{2} * m* (0.330)^2$

=> $m = 1612.5 \ kg$

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2 years ago

A pulse waveform with a frequency of 10 kHz is applied to the input of a counter. During 100 ms, how many pulses are counted?

bixtya [17]

Answer:

n = 1000 pulses

Explanation:

Given that,

The frequency of a pulse waveform, $f=10\ kHz=10^4\ Hz$

To find,

The number of pulses counted during 100 ms.

Solution,

The frequency of a pulse waveform is equal to the number of pulses per unit time. It is given by :

$f=\dfrac{n}{t}$

$n=f\times t$

$n=10^4\ Hz\times 100\times 10^{-3}\ s$

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So, there are 1000 pulses counted in a pulse waveform.

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3 years ago

Which is not a form of ionizing radiation

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Answer:

X rays, gamma rays, alpha particles, and beta particles are ionizing radiation

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2 years ago

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Two forces act on a moving object that has a mass of 27 kg. One force has a magnitude of 12 N and points due south, while the ot

tatuchka [14]

Answer:

mag (a) = 0.7707 m/s^2

a = - 0.62963 i - 0.4444 j

Explanation:

Given:

- Force 1 , F_1 = - 12 j

- Force 2, F_2 = - 17 i

- mass of the object m = 27 kg

Find:

What is the acceleration of the object

Solution:

- The relation between the Force vector and the acceleration vector of an object can be given by the Newton's Second Law of motion:

F = m*a

Where a is the acceleration vector.

(-17 i - 12 j ) = m*a

a = (-17 i - 12 j ) / 27

a = - 0.62963 i - 0.4444 j

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mag (a) = sqrt ( (-0.62963)^ 2 + (-0.44444)^2 )

mag (a) = sqrt ( 433/729)

mag (a) = 0.7707 m/s^2

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2 years ago

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