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babunello [35]
4 years ago
12

the number of electrons in a copper penny is approximately 10 10^23. How large would the force be on an object if it carried thi

s charge and were repelled by an equal charge one meter away?
Physics
1 answer:
iVinArrow [24]4 years ago
8 0

Answer:

0.000230144 N

Explanation:

n = Number of electrons = 10\times 10^{23}

q = Charge of electron = 1.6\times 10^{-19}\ C

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

r = Distance between obects = 1 m

The force would be

F=\dfrac{nkq^2}{r^2}\\\Rightarrow F=\dfrac{10\times 10^{23}\times 8.99\times 10^9\times (1.6\times 10^{-19})^2}{1^2}\\\Rightarrow F=0.000230144

The force would be 0.000230144 N

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Let, 1st force = a

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