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yanalaym [24]
4 years ago
9

A cyclist accelerates from 0 m/s to 10 m/s in 3 seconds. What is his acceleration?

Physics
1 answer:
mr_godi [17]3 years ago
3 0

Answer:

3.33 m/s^2

Explanation:

a =  \frac{v \:  -  \: u}{t}

V = final velocity ( 10m/s^2 )

U = Initial velocity ( 0m/s^2 )

t = Time taken ( 3 s )

a =  \frac{10 - 0}{3}  = 3.3333......

approximately = 3.33 m/s^2

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Which nanotechnology product would most likely help the
KonstantinChe [14]

Answer: OLEDs

Explanation:

The nanotechnology uses the surface of the carbon materials to generate the electricity. The evaporation of water on the surface of carbon materials helps in generation of electrical energy due to generation of thermal energy.

OLEDs can be defined as solid-state devices that comprises of organic molecules like carbon that will create electricity by exposing a surface for generation of thermal energy.

5 0
4 years ago
What is the melting point of substance A?
Misha Larkins [42]

Answer:

Solids are easily recognized by their ability to retain a fixed shape and definite volume. Particles making

up a solid are held together in a rigid form. They are not free to move about or slide past one another and

the solid does not have the ability to flow. (Although the particles of a solid do not move position to position, they do have motion in that they are constantly vibrating.

To change the temperature of a solid, heat energy must be added. The amount of heat energy that changes

the temperature of 1.0 g of a solid by 1.0°C is called its specific heat (c). Each substance has its own

specific heat. The specific heat of ice is 2.1 Joules/g°C. In other words we must supply 1.0 gram of ice

with 2.1 Joules of heat energy to raise its temperature by 1.0 °C.

The general equation for calculating heat energy to change the temperature of a solid is:

Heat = Mass x Specific Heat (solid) x Temperature Change

Q = m c DT

10 g 10 g 10 g 10 g 10 g 10 g

Calculate the heat necessary to change 10 g of ice(s) at -20 °C to 10 g of ice(s) at 0°C. (A-B)

Q = mc∆T = (10 g) (2.1 J/g°C) (20°C) = 420 J

If you continue to add heat energy once the temperature of the ice reaches 0°C , the heat absorbed is called

the heat of fusion (Lf). This heat is used to cause a change of phase (from a solid to a liquid). This heat is

increasing the potential energy of the molecules of the solid. No temperature change takes place. Each

substance has its own heat of fusion. The heat of fusion for ice is 340 Joules/g. Exactly the same amount

of heat is given up when 1.0 g of water is changed to ice. This heat is called the heat of crystallization.

The general equation for calculating heat energy to change a solid to a liquid is:

Heat = Mass x Heat of Fusion

Q = m Lf

Calculate the heat necessary to change 10 g of ice(s) at 0°C to 10 g of water(l) at 0°C.(B-C)

Explanation:

Q = mLf = (10 g)( 340 J/g) = 3400 J

3 0
3 years ago
You are standing 10 meters from a light source. Then, you back away from the light source until you are 20 meters away from it.
aliya0001 [1]
From my new perspective, the new intensity of the
light source has decreased by a factor of four.
7 0
3 years ago
Read 2 more answers
The velocity of an ocean wave is 5m/s. The distance between crests is 3m. What is the frequency of the wave
alexgriva [62]

Answer:

1.67m

5m/s

Explanation:

Wavelength of the wave = 3m

Speed of the wave  = 5m/s

The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.

 To find the frequency ;

        V = f∧

V is the speed of the wave

f is the frequency

∧ is the wavelength

  Insert the parameters and find the frequency;

        f  = V/ ∧   = 5 / 3  = 1.67Hz

The rate at which the wave passed a given point is the speed of the wave and it is 5m/s

4 0
3 years ago
A 2cm length of wire centered on the origin carries a 20A current directed in the positive y direction. Determine the magnetic f
skad [1K]

Answer:

The magnetic field at a distance x = 5 m is 1.59 nT

Explanation:

Length of the wire, L = 2 cm = 0.02 m

Current, I = 20 A

x = 5 m

Magnetic field at a distance x = 5 m due to an infinitely long wire is given by:

B = \frac{\mu_{o}IL}{4\pi x\sqrt{x^{2} + L^{2}}}

B = \frac{4\pi\times 10^{- 7}\times 20\times 0.02}{4\pi \times 5\sqrt{5^{2} + 0.02^{2}}} = 1.59\times 10^{- 9}\ T

3 0
3 years ago
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